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mel-nik [20]
4 years ago
9

DIVIDING ALGEBRAIC FRACTIONS

Mathematics
2 answers:
aleksandr82 [10.1K]4 years ago
7 0
Solve by factoring and using the principal of zero products 4x^2= -11x-6. Write it .... Let f(x) = x^3<span> + 3x ^</span>2<span>+ </span>4x<span> - 7 and g(x) = -7x^4 + 5x^</span>3<span> +x^</span>2<span> - 7.</span>
Anna71 [15]4 years ago
6 0
              <span> 125y3 + 8x3 = { sum of cubes }
(2x)^3 + (5y)^3 = (2x+5y)(4x^2 - 10xy + 25y^2)
Answer
4x^2 - 10xy + 25y^2  it takes to long to through go through steps </span>
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0.65 is 10 times as much as and 1/10 of
sesenic [268]

Answer:

Step-by-step explanation:

0.65 is 10 times as much as 0.065

and it is 1/10 of 6.5

4 0
3 years ago
Explain why two obtuse angles cannot be supplementary to another.
Nuetrik [128]
It's impossible. Supplements need to add up to 180 degrees, and in order to be obtuse, the angles would both need to be larger than 90 degrees.
5 0
3 years ago
Read 2 more answers
Please answer 1,2,3, and 4
Anika [276]

Answer:

<u><em>1: "An equilateral triangle is never an obtuse triangle" & "An equilateral triangle is never an isosceles triangle." </em></u>

<u><em> </em></u>

<u><em>2: Acute Isosceles Triangle </em></u>

<u><em> </em></u>

<u><em>3: False! Option B. </em></u>

<u><em> </em></u>

<u><em>4: D</em></u>

Step-by-step explanation:

2: Isosceles Triangles have two equal sides. An acute triangle (or acute-angled triangle) is a triangle with three acute angles (less than 90°). An obtuse triangle (or obtuse-angled triangle) is a triangle with one obtuse angle (greater than 90°) and two acute angles.

3: An <u>equilateral triangle</u> is a triangle in which all the sides and all the angles are equal.

4: In order for a triangle to be <u>isosceles</u>, it has to have two same sides. For a triangle to be <u>equilateral</u>, all sides and angles need to be the same. Refer to reasoning in Question 2 for next explanation.

5 0
3 years ago
Simplify: (c+4/c^2+5x+6)/(3c^2+12c/2c^2+5c-3)
juin [17]
(c+4/c^2+5c+6)/(3c^2+12c/2c^2+5c-3)= (c+4)/(c^2+5c+6) Multiplied by (2c^2+5c-3)/3c^2+12c= 2c^3+5c^2-3c+8c^2+20c-12/3c^4+12c^3+15c^3+60c^2+18c^2+72= 2c^3+13c^2+17c-12/3c^4+27c^3+78c^2+72c
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3 years ago
Work out the size of angle a
satela [25.4K]

Answer:thre

Step-by-step explanation:

8 0
3 years ago
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