Answer:
Implementing client side validation
Explanation:
Given that this type of attack is known as Integer Overflow, the best means or practices to prevent this kind of attack is " implementing client-side validation."
This is because implementing client-side validation assists to prevent the validation errors that will arise from the integer overflow thereby resulting in a reduction of the network and server load.
Hence, in this case, the correct answer is "Implementing the client-side validation."
It would be better if we could see the options, fully. But from what I can see, it should be B.
Answer:
#include <stdio.h>
#include <string.h>
int main(void) {
char simonPattern[50];
char userPattern[50];
int userScore;
int i;
userScore = 0;
scanf("%s", simonPattern);
scanf("%s", userPattern);
for(i = 0;simonPattern[i]!='\0';i++){
if(simonPattern[i]!=userPattern[i]){
userScore=i;
break;
}
}
printf("userScore: %d\n", userScore);
return 0;
}
Explanation:
- Use a for loop that runs until it does not reach the end of simonPattern.
- Check whether the current index of simonPattern and userPattern are not equal and then assign the value of i variable to the userScore variable and break out of the loop.
- Finally display the user score.
Y’all just asking for people do your work, literally not even a question
Answer:
0010
Explanation:
Serially left shifted means that the left most bit will enter the register first. The left most bit already stored in the register will move out of the sequence. The "bold" bits mentioned below highlight these left most bits:
Initial State of the Register:
0000
Group of bits entering:
1011
<u>First Clock Cycle:</u>
0000 <em>(This bold bit will move out)</em>
1011 <em>(This bold bit will move in from right side, shifting the whole sequence one place to the left).</em>
The resulting Sequence:
0001
<u>Second Clock Cycle:</u>
0001 <em>(This bold bit will move out)</em>
1011 <em>(This bold bit will move in from right side, shifting the whole sequence one place to the left).</em>
The resulting Sequence:
0010 <em>(Final Answer)</em>
