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goldenfox [79]
3 years ago
12

When a primitive type variable is passed as an argument to a method, what is passed into the receiving method's parameter variab

le
Computers and Technology
1 answer:
weqwewe [10]3 years ago
8 0

Answer:

The value of the primitive type variable is passed into the receiving method

Explanation:

Examples of primitive data types are integers, floats, real, double, character, byte, etc.

When any of these data types variables are passed to a method, the method which receives the variables receives the value of the variable being passed.

Take, for instance; the following code segment:

int doubleNum(int num){ ..... }

int main(){ ... num = 2; doubleNum(num);}

The above function doubleNum will receive the value of num (which is 2).

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Answer:

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3 years ago
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4 years ago
Read 2 more answers
I’m failing this class and i’m stuck on this one, this is the code from the last lesson:
serg [7]

lst=([])

def avgGPA(lst1):

   total = 0

   count = 0

   for x in lst:

       if type(x) == int:

           total += x

           count += 1

   return total/count

def GPAcalc(grade, weighted):

   grade = grade.lower()

   dictionary = {"a": 4, "b": 3, "c": 2, "d": 1, "f": 0}

   if weighted == 1 and grade in dictionary:

       lst.append(dictionary[grade]+1)

       return "Your GPA score is: " + str(dictionary[grade] + 1)

   elif weighted == 0 and grade in dictionary:

       lst.append(dictionary[grade])

       return "Your GPA score is: " + str(dictionary[grade])

   else:

       lst.append("Invalid")

       return "Invalid"

classes = int(input("How many Classes are you taking? "))

i = 0

while i < classes:

   print(GPAcalc(input("Enter your Letter Grade: "), int(input("Is it weighted? (1 = yes) "))))

   i += 1

print("Your weighted GPA is a "+str(avgGPA(lst)))

If you need me to change any code, I'll do my best. I hope this helps!

6 0
3 years ago
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