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podryga [215]
4 years ago
6

Mrs. J. is trying to get her third-grade students to remember to have their homework signed by a parent before bringing it to cl

ass. Students who remember every day for a month receive a gift card from a local bookstore. This is an example of a(n) __________.a. activity reinforcer.
b. possessional reinforcer.
c. consumable reinforcer.
d. manipulative reinforcer.
Mathematics
1 answer:
arsen [322]4 years ago
8 0

Answer: b. possessional reinforcer.

Explanation:

Possession reinforcement refers to a situation where a subject is motivated by material means i.e giving the subject a article as a reward. E.g, buying your child a bicycle for getting an A.

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BRAINLEIST!!!! You have a credit card with a balance of $754.43 at a 13.6% APR. You have $300.00 available each month to save or
Alex
We are given
P = $754.43
r = 13.6% annual

for a.
A = 150
for b.
A = 300

First, change the interest into effective monthly
i = (1 + 0.136/12)^12 - 1
Solve for i

Next, use the general formula
A = P i ( 1 + i)^n / (1 + 1)^n - 1
Subsitute P, i, and A for a and b.
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6 0
3 years ago
Ravi can type 6 words in 4 seconds. how many words can she type in 10 seconds.
nikdorinn [45]
15, first, you divide 6 by 4 and that will give you how many words Ravi can type per second, then multiply by 10.
5 0
3 years ago
Explain how to write and evaluate an algebraic expression. one more than the product of a number and seven, decreased by five; e
Cloud [144]
1) When it says more than, then you have to switch it so it will be 7n + 1 instead of 1+7n.
2) Because you then have to subtract by 5 you have to put the 7n + 1 in parentheses so it reads (7n + 1) - 5
3) And then to evaluate you just have to substitute n for 6
4) 7 * 6 = 42; 42+1 = 43; 43-5 = 38
5) The answer to this expression would be 38

Hope it helps :)

Please give brainliest
7 0
3 years ago
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Solve the equation after making an appropriate substitution. X^6-98x^3=3375
Leni [432]
Rearrange x^6-98x^3=3375 to give

x^6-98x^3-3375=0

Let x^3 be a variable 'p' and so we can write x^6 as x^6=(x^3)(x^3)=(p)(p)= p^2

Rewrite the equation in terms of 'p'

p^2-98p-3375 = 0

where a=1, b=-98, c=-3375

using the quadratic formula \frac{-b+ \sqrt{b^2-4ac} }{2a} and subsitute the value of a, b, c

p_1= \frac{-(-98)+ \sqrt{(-98)^2-4(1)(-3375)} }{2} =125

p_2= \frac{-(-98)- \sqrt{(-98)^2-4(1)(-3375)} }{2} =-27

There are two value of p; 125 and -27 

Now we find the value of x

Earlier we substitute x^3 for p and x^6 for p^2

When p=125, x= \sqrt[3]{125}=5
When p = -27, x= \sqrt[3]{-27}=-3

So the final answer is the two values of x; 

x = 5 OR x = -3
3 0
3 years ago
A Rhombus with diagonal 1 equal to 5 ft and diagonal 2 equal to 8 ft
Minchanka [31]

Answer:

Area = 20 ft²

Step-by-step explanation:

Area of a thrombus

½ × d1 × d2

½ × 5 × 8

20

4 0
4 years ago
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