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podryga [215]
3 years ago
6

Mrs. J. is trying to get her third-grade students to remember to have their homework signed by a parent before bringing it to cl

ass. Students who remember every day for a month receive a gift card from a local bookstore. This is an example of a(n) __________.a. activity reinforcer.
b. possessional reinforcer.
c. consumable reinforcer.
d. manipulative reinforcer.
Mathematics
1 answer:
arsen [322]3 years ago
8 0

Answer: b. possessional reinforcer.

Explanation:

Possession reinforcement refers to a situation where a subject is motivated by material means i.e giving the subject a article as a reward. E.g, buying your child a bicycle for getting an A.

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Step-by-step explanation:

A WOMEN WOULD OVER HER LIFE THE TFR SO IF YOU RELATE THAT TO GOATS THE MALE BRITISH AND THE FEMALE BIRTH WOULD BE DEFERRED SO THE PROBABILITY WOULD BE WORSE.

6 0
2 years ago
The temperature was 75° Fahrenheit. The temperature dropped at a rate of 10° per hour.
Zigmanuir [339]

Answer:

-5 degrees

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you started at 75 degrees. it dropped at a rate of 10 degrees per hour. It's been eight hours. 8 times 10 equals 80. It dropped a total of 80 degrees. the starting 75 degrees minus the current 80 degrees equals -5 degrees.

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3 years ago
Rick ordered a soda for $1.25 and wanted to order as many hotdogs as he could afford. Rick had $4.00 and each hotdog cost $0.75.
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3 years ago
(8x-4)+(17x-23)+(3x+17)=180
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7 0
3 years ago
3^x= 3*2^x solve this equation​
kompoz [17]

In the equation

3^x = 3\cdot 2^x

divide both sides by 2^x to get

\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3

Take the base-3/2 logarithm of both sides:

\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}

Alternatively, you can divide both sides by 3^x:

\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13

Then take the base-2/3 logarith of both sides to get

\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}

(Both answers are equivalent)

8 0
2 years ago
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