Let's find the derivative of that hyperbola in order to find a slope formula to help us with this equation. We already have an x and y value. The derivative is found this way: 
so 
. The derivative supplies us with the slope formula we need to write the equation. Sub in the x value of 3 to find what the slope is: 
. So in our slope-intercept equation, x = 3, y = 1, and m = -1/3. Use these values to solve for b. 
so b = 2. The equation, then, for the line tangent to that hyperbola at that given point is 
PLZ HELP I'm fr super confused I'll give BRAINLIEST plz show the work
2 answers:
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Answer:
Following are the function description to the given question:
Step-by-step explanation:
In the given-question, three functions are used, that can be defined as follows:
In function 1:
This function is also known as the modulus on the absolute value function, for example:
In the given in the above graph, that is
In function 2:
In this function, It is an algebraic function that is
It is also a part of the quadratic polynomial function, and its value is
In function 3:
In this function, it is the cubic polynomial equation that's value is
In the graph its value is: