Answer: x = 13
Step-by-step explanation:
Reorder the terms:
14 + 2x = 40
Solving
14 + 2x = 40
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-14' to each side of the equation.
14 + -14 + 2x = 40 + -14
Combine like terms: 14 + -14 = 0
0 + 2x = 40 + -14
2x = 40 + -14
Combine like terms: 40 + -14 = 26
2x = 26
Divide each side by '2'.
x = 13
Simplifying
x = 13
5/48, 3/16, 0.5, 0.75
It helps if you put the fractions in a calculator to change them into decimals.
Step-by-step explanation:
I'll do line A for you and you can use the formulas to solve lines B and C yourself, since its good for you to practice doing these questions yourself
a)
The gradient, m, is calculated using m = (y2-y1)/(x2-x1) where x1,x2,y1 and y2 can be any ordered pairs on the line. I'm going to use (4,0) and (7,3) as the 2 points.
m = (3-0)/(7-4) = 3/3 = 1
b)
The y-intercept is where the line intersects with the x-axis. In this case (0,-4)
c)
The equation of a linear line is y=mx+b (or c depending on which country you are from)
y = 1x-4
y=x-4
Now try the other 2 lines yourself!
If this answer has helped you, considered making this the brainliest answer!
Answer:
Greater fraction is

Step-by-step explanation:
we are given two fractions
and 
First fraction:

Second fraction:

We can simplify it


To compare them , firstly we should make common denominator
denominators are 7 and 5
so, common denominator is

now, we can make each denominator as 35





so, we can see that both fractions have common denominator =35
and greater numerator is 30
so,
Greater fraction is

Answer:
D. x=29.37
Step-by-step explanation:
To answer this question you have to understand how log work. Log is the abbreviation of logarithm and it works as an inverse function of exponentiation.
The rules should be like this:
Variable a in the equation is called base. If it left empty you can assume its base 10. The log in this question using 5 as a base. Variable b will be x and variable c will be 2.1
Now, let's change the variable of the equation using the information from the question.