We can use trial or error method here...
If we take 4 table, 4*5 = 20 and 4*7 = 28. 20+28 = 48.
20 : 28 = 5 : 7
So, there are 20 boys and 28 girls in a school play and there are 8 girls more than boys.
If you look over tables and try it out, only 4 table works for the given ratio.
Answer:
About 9.38
Step-by-step explanation:
Since the
is between the
and the
which simplified is 9 and 10, you just need to guess and check. Eventually you'll get about 9.38 (I used Google cause I was lazy) And if it isn't between the numbers 9 & 10, it's wrong.
Answer:
a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b)0.6004
c)19.607
Step-by-step explanation:
Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2
X ~ Poisson(A) where 
a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar

50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55
So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment
Let X denotes the number of grams to be eaten before another fragment is detected.

c)The expected number of grams to be eaten before encountering the first fragments :
s
Answer: b and d
Step-by-step explanation:
if any concerns or questions on solution, just comment