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4 years ago

8 and 1/5 - 3 and 4/5

Mathematics

1 answer:

KengaRu [80]4 years ago

4 0

Answer:

4.4

Step-by-step explanation:

I believe the answer is 4.4 or 22/5.

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A line passes through the point (9,1) and has a slope of 2.Write an equation in slope-intercept form for this line.

bogdanovich [222]

Answer:

y = 2x-17

Step-by-step explanation:

We have a point and a slope, we can write the equation in point slope form and then convert to slope intercept form

y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point

y-1 = 2(x-9)

Distribute

y-1=2x-18

Add 1 to each side

y-1+1 = 2x-18+1

y = 2x-17

This is slope intercept form

4 0

3 years ago

Whats 2+2? free brainliest btw

Debora [2.8K]

Answer:

Step-by-step explanation: 4 the answer is 4

3 0

3 years ago

Read 2 more answers

Find gradient and y-intercept of Y=3x-5

NemiM [27]

Answer:

Slope m (Gradient) = 3

y-intercept: (0, -5)

General Formulas and Concepts:

Algebra I

Slope-Intercept Form: y = mx + b

m - slope

b - y-intercept

Step-by-step explanation:

Step 1: Define

y = 3x - 5

Step 2: Break function

Slope m = 3

y-intercept b = -5

8 0

3 years ago

Read 2 more answers

Phoebe usually drives to work each day on a 12-mile road that is currently closed for construction. While the road is closed she

Mumz [18]

The total distance phoebe has to drive each day (round trip) while her usual route is closed is 42 miles

<h3>What is a Pythagoras theorem?</h3>

The square of the longest side is equal to the square of the sum of the othersides.

Before we can calculate the total distance, we will need to get the hypotenuse on both sides using the Pythagoras theorem as shown:

H^2= 12^2 + 9^2

H² = 144 + 81

H² = 225

H = 15

For the other hypotenuse

h² = 12² + 5²

h² = 144 + 25

h² = 169

h = 13 mils

The total distance = 5 + 15 + 9 + 13

The total distance = 42 miles

The total distance phoebe has to drive each day (round trip) while her usual route is closed is 42 miles

Learn more on Pythagoras theorem here: brainly.com/question/12306722

3 0

2 years ago

A ½in diameter rod of 5in length is being considered as part of a mechanical linkagein which it can experience a tensile loading

Evgesh-ka [11]

Answer:

a. Maximum Load = Force = 27085.09 N

b. Maximum Energy = 3.440 Joules

Step-by-step explanation:

Given

Rod diameter = ½in = 0.5in

Length = 5in

Young's modulus = 15.5Msi

By applying the 0.2% offset rule,

The maximum load the rod can hold before it gets to breaking point is given as follows by taking the strain as 0.2%

Young Modulus = Stress/Strain ------- Make Stress the Subject of Formula

Stress = Strain * Young Modulus

Stress = 0.2% * 15.5

Stress = 0.002 * 15.5

Stress = 0.031Msi

Calculating the area of the rod

Area = πr² or πd²/4

Area, A = 22/7 * 0.5^4 / 4

A = 22/7 * 0.25 / 4

A = 5.5/28

A = 0.1964in²

The maximum load that the rod would take before it starts to permanently elongate is given by

Force = Stress * Atea

Force = 0.031Msi * 0.1964in²

Force = 31Ksi * 0.1964in²

Force = 6.089Ksi in²

Force = 6.089 * 1000lbf

Force = 6089 lbf

1 lbf = 4.4482N

So, Force = 6089 * 4.4482N

Force = 27085.09 N

Using Strain to Energy Formula

U = V×σ²/2·E

Where V = Volume

V = Length * Area

V = 5 in * 0.1964in²

V = 0.982in³

σ = Stress = 0.031Msi

= 0.031 * 1000Ksi

= 31Ksi

= 31 * 1000psi

= 31000psi

E = Young Modulus = 15.5Msi

= 15.5 * 1000Ksi

= 15.5 * 1000 * 1000psi

= 15500000psi

So,

Energy = 0.982 * 31000²/ ( 2 * 15500000)

Energy = 943,702,000/31000000

Energy = 30.442in³psi

------- Converted to ftlbf

Energy = 2.537 ftlbf

-------- Converted to Joules

Energy = 3.440 Joules

7 0

4 years ago