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4 years ago

A line passes through the point (9,1) and has a slope of 2.Write an equation in slope-intercept form for this line.

Mathematics

1 answer:

bogdanovich [222]4 years ago

4 0

Answer:

y = 2x-17

Step-by-step explanation:

We have a point and a slope, we can write the equation in point slope form and then convert to slope intercept form

y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point

y-1 = 2(x-9)

Distribute

y-1=2x-18

Add 1 to each side

y-1+1 = 2x-18+1

y = 2x-17

This is slope intercept form

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The height of a free falling object at time t can be found using the function, h(t) = - 12t2 + 36t. Where h(t) is the height in

never [62]

For this case we have the following equation:
h (t) = - 12t2 + 36t
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t2 = 3
Therefore, the time it takes the object to hit the ground is:
t = 3 s
Answer:
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earnstyle [38]

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Step-by-step explanation:

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Find the x-values that are solutions of the equation 5cot^2x-15=0

julia-pushkina [17]

First solve for the trig function 'cot'
$cot^2 x = \frac{15}{5} = 3$

Next take the sqrt of both sides (include plus/minus)
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Now take reciprocal of both sides, this will change trig function to 'tan'
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$tan x = \pm \frac{1}{\sqrt{3}} = \pm \frac{\sqrt{3}}{3}$

Finally use the unit circle or inverse tan on your calculator to find x.
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$x = \frac{\pi}{6}, \frac{5\pi}{6}, \frac{7\pi}{6}, \frac{11\pi}{6}$

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