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alexdok [17]
3 years ago
9

A study was conducted to determine whether the mean braking distance of four-cylinder cars is greater than the mean braking dist

ance of six-cylinder cars. A random sample of 20 fourcylinder cars and a random sample of 20 six-cylinder cars were obtained, and the braking distances were measured. (a) What would be the appropriate hypothesis test for this analysis? (i) t-test for two independent samples (ii) t-test for dependent samples (iii) z-test for population mean (iv) correlation
Mathematics
1 answer:
ankoles [38]3 years ago
6 0

Answer:

a) t-test for two independent samples

b) For this case we have two different samples and both are less than 30 and we don't have any info about the populationd deviation's. So for this case the most appropiate test is the t-tes for two independent samples

Step-by-step explanation:

The independent t-test, is known as two sample t-test or independent-samples t-test, is an statistical test used to " determines whether there is a statistically significant difference between the means in two unrelated groups"

The system of hypothesis could be on this case like this:

Null hypothesis: \mu_1 = \mu_2

Alternative hypothesis: \mu_1 \neq \mu_2

Or equivalently:

Null hypothesis: \mu_1 - \mu_2 = 0

Alternative hypothesis: \mu_1 -\mu_2 \neq 0

The statistic to check the hypothesis is given by:

t=\frac{(\bar X_1 -\bar X_2)-(0)}{\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}}

And this statistic follows a t distribution with degrees of freedom df=n_1 +n_2 -2

We can check the hypothesis using the p value method or the critical approach, but we need to have a significance level.

Part a

i) t-test for two independent samples

Part b

Explain the rationale for your selection in (a). Specifically, why would this be the appropriate statistical approach?

For this case we have two different samples and both are less than 30 and we don't have any info about the populationd deviation's. So for this case the most appropiate test is the t-test for two independent samples

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Elden [556K]
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3 years ago
Question is down below
Bingel [31]

This is a great question!

To determine the probability with which two sweets are not the same, you would have to subtract the probability with which two sweets are the same from 1. That would only be possible if she chose 2 liquorice sweets, 5 mint sweets and 3 humburgs -

Probability( 2 Liquorice) = 12 / 20 * 11 / 19

As you can see, the first time you were to choose a Liquorice, there would be 12 out of the 20 sweets present. After taking that out however, there would be respectively 11 Liquorice out of 19 remaining. Apply the same concept to each of the other sweets -

Probability(2 Mint ) = 5 / 20 * 4 / 19,\\Probability( 2 Humbugs ) =  3/20 * 2/19

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Calculate the probability of drawing 2 of each, add them together and subtract from one to determine the probability that two sweets will not be the same type of sweet!

1-\left(\frac{132}{380}+\frac{20}{380}+\frac{6}{380}\right) =\\\frac{111}{190}

<u><em>Thus, the probability should be 111 / 190</em></u>

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4 years ago
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Answer:

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Step-by-step explanation:

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