Marcellus has a pitcher that contained 5/8 gallon limeade. Marcellus drank 1/4 gallon of the limeade, and Marcy drank 1/8 gallon
. What fractional part of a gallon of limeade remained in the pitcher?
1 answer:
Answer:
2/5
Step-by-step explanation:
Given Marcellus drank 1/4 gallon of the limeade and Marcy drank 1/8 gallon of the limeade
Given that only 5/8 portion of the pitcher contains limeade
Total amount drunk = amount drunk by Marcellus + amount drunk by Marcy
Total amount drunk =
= 
The amount of Limeade remained = The amount initially - the amount drunk
The amount remained =
= 
Fractional part = amount remained / amount initially =
= 
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