What is y/6 - 3 = -11

A line passes through the point (-8, 6) and has a slope of 3/2

Vladimir79 [104]

Answer:

y-6=3/2(x+8)

Step-by-step explanation:

so the point slope form is y-y₁=m(x-x₁)

so enter the points (-8, 6)

y-6= 3/2(x-(-8))

y-6=3/2(x+8)

3 0

3 years ago

Read 2 more answers

Please help me, my teacher said that only 3 of them are right. so please get three right. please. The second file attached is th

iren [92.7K]

Answer:

What are you supposed to do

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.9 minutes and a standard deviation of 2.9

Eva8 [605]

Answer:

a) 0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

b) 0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes

c) 0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 8.9 minutes and a standard deviation of 2.9 minutes.

This means that $\mu = 8.9, \sigma = 2.9$

Sample of 37:

This means that $n = 37, s = \frac{2.9}{\sqrt{37}}$

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

320/37 = 8.64865

Sample mean below 8.64865, which is the p-value of Z when X = 8.64865. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{8.64865 - 8.9}{\frac{2.9}{\sqrt{37}}}$

$Z = -0.53$

$Z = -0.53$ has a p-value of 0.2981

0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

275/37 = 7.4324

Sample mean above 7.4324, which is 1 subtracted by the p-value of Z when X = 7.4324. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{7.4324 - 8.9}{\frac{2.9}{\sqrt{37}}}$

$Z = -3.08$

$Z = -3.08$ has a p-value of 0.001

1 - 0.001 = 0.999

0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Sample mean between 7.4324 minutes and 8.64865 minutes, which is the p-value of Z when X = 8.64865 subtracted by the p-value of Z when X = 7.4324. So

0.2981 - 0.0010 = 0.2971

0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes

7 0

2 years ago

Will give brainliest answer

ArbitrLikvidat [17]

Answer:

180°

Step-by-step explanation:

Connecting any point of original figure with the same of the image

For example point C with C'

The line goes through the origin (0, 0)

<u>And the coordinates changed as:</u>

(x, y) → (-x, -y)

It means the rotation is 180°

4 0

3 years ago

I need help it’s super confusing

steposvetlana [31]

Answer:

Range = 58

Mean = 25.81

Median = 17

Mode = 2, 9, 11, 12, 16, 17, 18, 41, 48, 50, 60

Upper Quartile = 11

Lower Quartile = 48

Step-by-step explanation:

Start by putting all of the values in order from least to greatest.

16, 18, 12, 9, 17, 2, 41, 48, 50, 60, 11

becomes

2, 9, 11, 12, 16, 17, 18, 41, 48, 50, 60

Range

The range is the difference between the highest and lowest value. So in this case, it's 58, because 60 - 2 = 58

Mean

The mean is another word for the average. To calculate the average, add all of the values and divide the sum by the number of values.

2 + 9 + 11 + 12 + 16 + 17 + 18 + 41 + 48 + 50 + 60 = 284

There are 11 values, so divide the sum (284) by 11:

284 / 11 = 25.8181818.

That rounds to 25.81

Median

The median is the middle value of the data set.

In 2, 9, 11, 12, 16, 17, 18, 41, 48, 50, 60 the middle value is 17. It has 5 values on each side of it.

Mode

The mode is the number that appears the most in the data set. Each value only appears once, so the mode is the entire list of numbers. 2, 9, 11, 12, 16, 17, 18, 41, 48, 50, 60

Upper Quartile

The upper quartile of a data set is the median of the numbers that are to the left of the median for the entire data set. The median is 17, so the numbers to the left are 2, 9, 11, 12, and 16. The median of those is 11 because it is in the middle. So the upper quartile is 11.

Lower Quartile

The lower quartile is found the same way the upper quartile is, but it's the median of the numbers to the <em>right</em>. The numbers to the right of 17 are

18, 41, 48, 50, and 60. The median of those is 48 because it's in the middle. So the lower quartile is 48.

5 0

3 years ago