Question

I have 200 coins to put into 4 bags I put the coins into each bag so that each bag has 2 mote coins than the one before How many coins are on each bag

Answer 1

First bag has 47 coins and second bag has 49 coins and third bag has 51 coins and fourth bag has 53 coins

Solution:

Given that,

Total number of coins = 200

Number of bags = 4

I put the coins into each bag so that each bag has 2 more coins than the one before

Therefore,

Each bag has 2 more coins than the one before. Based on this we can say,

Let "x" be the number of coins put in first bag

Then, x + 2 is the number of coins put in second bag

Then, x + 4 is the number of coins put in third bag

Then, x + 6 is the number of coins put in fourth bag

We know that,

Total number of coins = 200

$x + x + 2 + x + 4 + x + 6 = 200\\\\4x + 12 = 200\\\\4x = 200-12\\\\4x = 188\\\\x = 47$

Thus,

Coins put in first bag = x = 47

Coins put in second bag = x + 2 = 47 + 2 = 49

Coins put in third bag = x + 4 = 47 + 4 = 51

Coins put in fourth bag = x + 6 = 47 + 6 = 53

Thus number of coins in each bag are found