X = 5 cos t, y = 5 sin t Eliminate the perameter

1 answer:

7 0

$\bf \begin{cases}
x=5cos(t)\implies \frac{x}{5}=cos(t)\\\\
cos^{-1}\left( \frac{x}{5} \right)=cos^{-1}[cos(t)]\\\\ cos^{-1}\left( \frac{x}{5} \right)=\boxed{t}\\
----------\\
y=5sin(t)\implies y=5sin\left( \boxed{cos^{-1}\left( \frac{x}{5} \right)} \right)
\end{cases}$

just a matter of substitution

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3 years ago

Expand the following using either the Binomial Theorem or Pascal’s Triangle. You must show your work for credit. (x - 3)^5

Rudiy27

I used bionomial expansion up to and including the term $x^{3}$

$(-3 + x)^{5}$

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$-243 (1 + -\frac{1}{3}x) ^{5}$

n = 5
x = $- \frac{1}{3}x$

Binomial expansion:

$1 + nx + \frac{n(n-1) x^{2} }{2!} + \frac{n(n-1)(n-2) x^{3} }{3!}$

Therefore:

$1 + (5*- \frac{1}{3}x) + \frac{5(4) (- \frac{1}{3}x)^{2} }{2} + \frac{5(4)(3) (- \frac{1}{3}x)^{3} }{6}$

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$1 - \frac{5}{3} x + \frac{10}{9} x^{2} - \frac{10}{27} x^{3} 

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Multiply by -243

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3x-5=4x+2can i get help anyone

faltersainse [42]

Answer:

3(x+5) = 4x

Step-by-step explanation:

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3 years ago

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