Answer:
see explanation
Step-by-step explanation:
Under a reflection in the line y = - x
a point (x, y ) → (- y, - x )
Thus
F(- 4, - 1 ) → F'(1, 4 )
G(- 10, 4 ) → G'(- 4, 10 )
Remark
You know the most about the trip on the way back and the total of the two trips.
Way Back
r = 30 mph
d = distance traveled
t = t - 1 where t = the time to go there which we know nothing about
Total Distance
2d = 25 mph * (t + t - 1)
2d = 25 * (2t - 1)
2d = 50t - 25 Divide by 2
2d = 50t/2 - 25/2
d = 25t - 12.5
Equation coming back
d = 30*(t - 1)
d = 30t - 30
Comment
Since the distances are the same, equate them.
Solution
25t - 12.5 = 30t - 30 Subtract 25t from both sides
25t - 25t -12.5 = 30t - 25t - 30 Combine like terms
-12.5 = 5t - 30 Add 30 to both sides
-12.5 + 30 = 5t - 30 + 30 Combine
17.5 = 5t Divide by 5
17.5/5 = t Divide and Switch
t = 3.5
t is the time going there
t - 1 is the time coming back
Total time = 2*t - 1 = 2*3.5 - 1 = 6
The total time is 6 hours. Answer
<span>|4x + 1| ≤ 5
Subtract 1 from both sides
|4x| <= 5
Divide both sides by 4
Final Answer: |x| <= 1.25
I can't graph it though.</span>
Answer:
i dont know the answer but ask someone smarter
Step-by-step explanation:
