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3 years ago

What is 6.25 as a fraction?

2 answers:

6 0

6 1/4 you would keep the whole number. 25 is 1/4 of 100 It is in the hundredths place so you would put the number over 100 and simplify. Hope this helps!

Alik [6]3 years ago

4 0

Wells since there's a decimal theres a whole number so its 6 and .25 as a fraction is 1/4 so its 6 1/4

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4/3(6y+21)-17>43 help pls

dezoksy [38]

Answer:

Step-by-step explanation:

4/3(6y+21)-17=43

move all terms to the left:

4/3(6y+21)-17-(43)=0

Domain of the equation: 3(6y+21)!=0

y∈R

We add all the numbers together, and all the variables

4/3(6y+21)-60=0

You multiply all the terms by the denominator

-60*3(6y+21)+4=0

multiply elements

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3 years ago

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PIT_PIT [208]

Answer:

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Step-by-step explanation:

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3 years ago

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Maurinko [17]

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3 years ago

According to the manufacturer of a backup UPS device, the normal output voltage is 120 volts. The sample of 40 measured voltage

anyanavicka [17]

Answer:

z = 1.83<1.96

null hypothesis is accepted

The sample is came from a population mean

Step-by-step explanation:

Step :-1

The sample of 40 measured voltage amounts from a unit have a mean of 123.59 volts and a standard deviation of 0.31 volts

given sample size n =40

mean of the sample ×⁻ = 123.59 volts

standard deviation of sample σ = 0.31 volts

Step2:-

Null hypothesis :-

the sample is from a population with a mean equal to 120 volts.

H₀ : μ =120

Alternative hypothesis:-

H₁ : μ ≠120

level of significance:- α =0.05

Step 3:-

The test statistic

$z = \frac{x_{-}-mean }{\frac{S.D}{\sqrt{n} } }$

substitute values and simplification

$z = \frac{123.59-120}{\frac{0.31}{\sqrt{40} } }$

on simplification we get the calculated value

z = 1.83

The tabulated value z =1.96 at 0.05 % level of significance

Conclusion:-

Calculated Z < The tabulated value z =1.96 at 0.05 % level of significance

so the null hypothesis is accepted

The sample is came from a population mean

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hichkok12 [17]

Answer:

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Step-by-step explanation:

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