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Sever21 [200]
3 years ago
10

Age c) The group is planning to build a fence around the garden. How many yards of fencing materials do they need for the fence?

Show your work. (3 points—2 points for finding the value of side b and 1 point for finding the perimeter of the garden)
​
Mathematics
1 answer:
FromTheMoon [43]3 years ago
3 0

Answer:

Step-by-step explanation:

The perimeter is obtained by taking the sun of the fence :

Outer fencing :

Let's obtain b :

From Pythagoras :

b² = 15² - 12²

b = sqrt(225 - 144)

b = 9

Outer fencing = 2(12+6) + 2(8+9)

= 2(18) + 2(17)

= 36 + 34

= 70

Inner fencing :

(8 + 9 + 12 + 6 + 15 + 10) = 60

(70 + 60) = 130 yards

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In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p
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Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is  \frac{23}{30} or 0.76

Step-by-step explanation:

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Total number of students in the class = 30

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Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

P(A \cup B)=P(A)+P(B)-P(A \cap B)---------------(1)

where

P(A) = Probability of choosing  a student playing basket ball

P(B) =  Probability of choosing  a student playing base ball

P(A \cap B) =  Probability of choosing  a student playing both the games

<u>Finding  P(A)</u>

P(A) = \frac{\text { Number of students playing basket ball }}{\text{Total number of students}}

P(A) = \frac{19}{30}--------------------------(2)

<u>Finding  P(B)</u>

P(B) = \frac{\text { Number of students playing baseball }}{\text{Total number of students}}

P(B) = \frac{12}{30}---------------------------(3)

<u>Finding P(A \cap B)</u>

P(A) = \frac{\text { Number of students playing both games }}{\text{Total number of students}}

P(A) = \frac{8}{30}-----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}

P(A \cup B)= \frac{31}{30} -\frac{8}{30}

P(A \cup B)= \frac{23}{30}

7 0
3 years ago
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