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Pavel [41]
3 years ago
13

5 less than a number is equivalent to 1 more than three times the number. what is the number

Mathematics
1 answer:
Studentka2010 [4]3 years ago
7 0

Answer:

X = -3

Step-by-step explanation:

x - 5 = 3x + 1

-6 = 2x

x = -3

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

;)

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Varvara68 [4.7K]

Answer:/?idk

Step-by-step explanation:


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3 years ago
Suppose you just received a shipment of ten televisions. two of the televisions are defective. if two televisions are randomly​
amid [387]

Try this solution:

1. for probability of both televisions work:

P_{2w}=\frac{C^2_8}{C^2_{10}}=\frac{7*8}{9*10}=0.6(2)

2. for probability of at least on is defective (it means, the sum = one is defective and two are defective):

P_{1d}=\frac{C^1_2C^1_8}{C^2_{10}}=\frac{4*8}{9*10}=0.3(5) - for P(1defective);

P_{2d}=\frac{C^2_2}{C^2_{10}}=\frac{2}{9*10}=0.0(2) - for P(2defective);

totaly for at least one is defective:

P_{at \ least \ 1 \ d}=P_{1d}+P_{2d}=\frac{16}{45} +\frac{1}{45} =0.3(7)

5 0
3 years ago
Divide 12x^4+17^3+8x-40 by x-2
chubhunter [2.5K]

Answer:

12x^3 + 24x^2 + 48x + 104 + (5081/x-2)

Step-by-step explanation:

12x^4 + 17* (17*17) + 8x -40/ x-2

1. remove the parenthesis

12x^4 + !7 * 17 * 17 + 8x -40 / x-2

2. multiply 17 by 17

12x^4 + 289 * 17 + 8x -= 40 /x-2

3. multiply 289 by 17

12x^ = 4913 + 8x - 40 / x-2

4. move 4913

12x^4 + 8x + 4913 - 40 / x-2

5. subtract 40 from 4913

12x^4 + 8x + 4873 / x-2

6. set up polynomials to be divided. if there is not a term for every exponent, insert one with a value of 0

x-2 into 12x^4 + 0x^3 + 0x^2 + 8x + 4873

7. divide the highest order term  in the dividend 12x^4 by the highest order term in divisor x = 12x^3

8. multiply by new quotient term

12x^3 * x-2 = 12x^4 -24x^3

9. the expression needs to be subtracted from the dividend, so change all the signs in 12x^4 - 24x^3

12x^4 + 0x^3 - 12x^4 + 24x^3

10. after changing the signs, add the last dividend from the multiplied polynomial to find new dividend

+24x^3

11.  pull the next term from the original dividend down into the current dividend

+24x^3 + 0x^2

12.  divide the highest order term in the dividend 24x^3 by the highest order term in divisor x = 24x^2

12x^3 + 24x^2

13. multiply new quotient by the divisor

24x^3 * x-2 = 24x^3 - 48x^2

14. the expression needs to be subtracted from the dividend, so change all the signs in 24x^3 - 48x^2

24x^3 + 0x^2 - 24x^3 + 48x^2

15. after changing the signs, add the last dividend from the multiplied polynomial to find new dividend

+48x^2

16. pull the next terms from the original dividend down to the current dividend

+ 48x^2 + 8x

17. divide the highest order term in the dividend 48x^2 by the highest order term in the divisor = 48x

12x^3 + 24x^2 + 48x

18. multiply the new quotient term by the divisor

48x * x - 2 = 48x^2 - 96x

19. the expression needs to be subtracted from the dividend, so change all the signs in 48x^2 - 96x

-48x^2 + 96x

20. after changing the signs, add the last dividend from the multiplied polynomial to find new dividend

48x^2 + 8x - 48x^2 + 96x

= 104x

21. pull the next terms from the original dividend down to the current dividend

+ 104x + 4873

22. divide the highest order term in the dividend 104x by the highest order term in the divisor x = 104

23. divide the new quotient by the divisor

104 * x -2 = 104x - 208

24. the expression needs to be subtracted from the dividend, so change all the signs in 104x - 208

104x + 4873 - 104x + 208 = 5081

25. the final answer is the quotient plus the remainder over the divisor

12x^3 + 24x^2 + 48x + 104 + (5081 / x - 2)

5 0
2 years ago
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olga_2 [115]

Answer:

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Step-by-step explanation:

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Sav [38]

Answer:

1.25b when b < 12 , 1b & then 0.75 b when b <u>> </u>12

Step-by-step explanation:

  • Price for b bagels = Price x Quantity

* Less than 12 bagels bought, cost $1.25 per bagel

So, price for b bagels, when (b < 12) = 1.25b

* 12 or more than 12 bagels bought, cost $1 upto first 12 bagels & 0.75b on each additional bagel

So, price for b bagels, when (b = 12) = b

So, price for b bagels, when (b > 12) = b + 0.75b' , where b' denotes extra b beyond 12

8 0
3 years ago
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