Answer: a = 5.5
Step-by-step explanation:
95 = -20a - 25 + 10
95 = -20a - 15
-20a = 110
a = 5.5
Answer:
144
Step-by-step explanation:
Length of 1 side is 12 so area is 12*12
Answer:
123
Step-by-step explanation:
if the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadth
90/15-7/15=83/15 the correct answer to this equation.
![\bf \qquad \qquad \textit{ratio relations} \\\\ \begin{array}{ccccllll} &Sides&Area&Volume\\ &-----&-----&-----\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array} \\\\ -----------------------------\\\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\ -------------------------------](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Cqquad%20%5Ctextit%7Bratio%20relations%7D%0A%5C%5C%5C%5C%0A%5Cbegin%7Barray%7D%7Bccccllll%7D%0A%26Sides%26Area%26Volume%5C%5C%0A%26-----%26-----%26-----%5C%5C%0A%5Ccfrac%7B%5Ctextit%7Bsimilar%20shape%7D%7D%7B%5Ctextit%7Bsimilar%20shape%7D%7D%26%5Ccfrac%7Bs%7D%7Bs%7D%26%5Ccfrac%7Bs%5E2%7D%7Bs%5E2%7D%26%5Ccfrac%7Bs%5E3%7D%7Bs%5E3%7D%0A%5Cend%7Barray%7D%20%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0A%5Ccfrac%7B%5Ctextit%7Bsimilar%20shape%7D%7D%7B%5Ctextit%7Bsimilar%20shape%7D%7D%5Cqquad%20%5Ccfrac%7Bs%7D%7Bs%7D%3D%5Ccfrac%7B%5Csqrt%7Bs%5E2%7D%7D%7B%5Csqrt%7Bs%5E2%7D%7D%3D%5Ccfrac%7B%5Csqrt%5B3%5D%7Bs%5E3%7D%7D%7B%5Csqrt%5B3%5D%7Bs%5E3%7D%7D%5C%5C%5C%5C%0A-------------------------------)
the ratio of the cost, is tandem to the ratio of the areas, because, to get the cost for the mulch, you have to first know how many square meters/feet have, and then you apply the cost evenly, now, the cost is just a factor, therefore, the ratio is retained.
