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3 years ago

PLZ HELP ANY1!!!!!!!!!!!

Mathematics

1 answer:

Ronch [10]3 years ago

3 0

Its the last one because you plug in the 20(x) for example y=20x
and your table looks like this
x 0/2/4
y 0/40/80 y x
because 20(2)=40 then you would do the same with the rest of the equation
20(4)= 80 there fore the last on is your answer

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1. If A = {a, b, c, d}, B={c, d, e, f}, C={x, y, z} find (A-B)

vitfil [10]

Answer

here

A={a,b,c,d}

B={c,d,e,f}

C={x,y,z}

A-B={e,f}

8 0

1 year ago

Someone help me out with this need a quick respond

ser-zykov [4K]

To get the perimeter of a circle you need to use the formula 2xpix r
so 2x 3.1416 x 2= 12.56
so the third one counting from left to right

8 0

3 years ago

Name the triangle with the following characteristics. sides: 5 cm, 6 cm, 7 cm; Angles: 75° and 60°. yeah

Verdich [7]

Answer:

Step-by-step explanation:

this triangle is regular one

we can't apply the pytahgorian theorem 5²+6²≠7²
the angles have different sizes 75≠60≠45
the sides have different lengths 5≠6≠7

6 0

3 years ago

KiRa [710]

Answer:

B. The probability of getting a red convertible is 0.10.

Step-by-step explanation:

Independent events:

Two events, A and B, are independent if the probability of both happening is the same as the multiplication of the probabilities of each happening, that is:

$P(A \cap B) = P(A) \times P(B)$

In this question:

Event A: Red car -> 0.25 probability

Event B: Convertible car -> 0.4 probability

Independent if:

The probability of getting a red convertible car is:

$P(A \cap B) = P(A) \times P(B) = 0.25*0.4 = 0.1$

Thus, the correct answer is given by option B.

5 0

2 years ago

Write an augmented matrix of each system. Then, solve each system using matrix notation. Describe the solution set in vector not

Naddik [55]

Answer:

The answer is below

Step-by-step explanation:

Given the system of equations:

x + y + 2z = 9

2x + 4y - 3z = 1

3x + 6y - 5z = 0

This system of equation can be solved using matrix. This done by first representing the equations as matrix and then solving:

The matrix form is:

$\left[\begin{array}{ccc}1&1&2\\2&4&-3\\3&6&-5\end{array}\right] \left[\begin{array}{c}x\\y\\z\end{array}\right] = \left[\begin{array}{c}9\\1\\0\end{array}\right] \\\\\\ \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}1&1&2\\2&4&-3\\3&6&-5\end{array}\right] ^{-1} \left[\begin{array}{c}9\\1\\0\end{array}\right] \\\\\\$

$\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2&-17&11\\-1&11&-7\\0&3&-2\end{array}\right] \left[\begin{array}{c}9\\1\\0\end{array}\right] \\\\\\ \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{c}1\\2\\3\end{array}\right]$

5 0

2 years ago