Question

Does anybody know the answer?

Answer 1

Answer:

$slop \ of \ y = \frac{1}{6} x +3 , m_1 = \frac{1}{6} \\\\slope \ of \ the \ line \ perpendicular \ to \ y = \frac{1}{6}x +3 ,\\m_1 \cdot m_2 = -1\\\frac{1}{6} \cdot m_2 = -1\\m_2 = -6$

$equation \ of \ line \ through \ (-3, 23) \ and \ slope \ m_2 = -6 \\\\(y - 23) = -6(x -(-3))\\y-23 = -6(x+3)\\y - 23 = -6x -18\\y=-6x-18+23\\y=-6x +5$

Answer 2

Answer:

-6x + 5

Step-by-step explanation:

Note that perpendicular lines have slopes that are negative reciprocals of each other

The slope of the initial line is m = 1/6

The negative reciprocal of 1/6 is -6/1 = -6

Thus we are looking for the equation of the line with slope -6 going through point (-3,23)

 

Use the point slope form y-y1 = m(x-x1)

y - 23 = -6(x-(-3))

y-23 = -6(x+3)

y-23 = -6x -18

y = -6x -18 + 23

y = -6x + 5

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