The standard deviation of the frequency distribution is 5.54
<h3>How to determine standard deviation?</h3>
The table of values is given as:
x f(x)
0-3 13
4-7 13
8-11 10
12-15 11
16-19 0
20-23 3
Rewrite the table by calculating the class midpoints:
x f(x)
1.5 13
5.5 13
9.5 10
13.5 11
17.5 0
21.5 3
Start by calculating the mean using:
This gives
Evaluate
The standard deviation is then calculated as:
So, we have:
Evaluate
Solve
Hence, the standard deviation is 5.54
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The answer to your question is b
Answer:
a.y'=-1
b.y'=-1
c.Yes
Step-by-step explanation:
We are given that consider a function
Implicit function: That function is a relation in which dependent variable can not be expressed in terms of independent variable
Explicit function: It is that function in which dependent variable can be expressed in terms of independent variable.
a.
Differentiate w.r.t x then we get
b.
Differentiate w.r.t x then we get
When we substituting the value of y obtained from part b into a solution of part a then we get
Hence, solutions are consistent.
