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andrezito [222]
3 years ago
5

Find the missing angle measure in ΔABC.

Mathematics
1 answer:
Otrada [13]3 years ago
4 0
The answer to your question is b
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What is the 14th term in the sequence an=-4n+13
mojhsa [17]
<span>We have the sequence that follows the pattern: a n = - 4 n + 13. If we want to calcelate the 14th term in this sequence ( or a 14 ), we have to substitute in this formula: n = 14. Then we will get: a 14 = - 4 * 14 + 13 a 14 = - 56 + 13, and finally: a 14 = - 43. Answer: The 14th term in the sequence is - 43.</span>
7 0
3 years ago
Can someone please help me with this geometry question please.
Irina-Kira [14]

Answer:

x=10/3

Step-by-step explanation:

Vertical angles are congruent and therefore are equal. Just set up an equation where the two angle values are equal to one another and solve with basic algebra.

7 0
3 years ago
How do you write 0.000565 in scientific notation?
MA_775_DIABLO [31]
It would be written as:

5.65 *10^-4

Remember, when writing scientific notation for a decimal, the power of 10 is always negative. In this case, since we're basically moving the decimal point for places to the right, the power of 10 is -4

Hope this helped! :)
7 0
3 years ago
A contaminant is leaking into a lake at a rate of R(t) = 1700e^0.06t gal/h. Enzymes that neutralize the contaminant have been ad
olasank [31]

Answer:

16,460 gallons

Step-by-step explanation:

This is a differential equation problem, we have a constant flow of contaminant into the lake, but also we know that only a fraction of that quantity of contaminant remains because of the enzymes. For that reason, the differential equation of contaminant's flow into the lake would be:

\frac{dQ}{dt} =1700exp(0.06t)*exp(-0.32t)\\\frac{dQ}{dt} =1700exp(-0.26t)\\

Then, we have to integrate in order to find the equation for Q(t), as the quantity of contaminant in the lake, in function of time.

\int\limits^0_t {dQ}=\int\limits^0_t {1700exp(-0.26t)dt}\\Q(t)=\frac{1700}{-0.26} exp(-0.26t)+C \\

Now, we use the given conditions to replace them in the equation, in order to solve for C

t_{0} =0\\Q_{0}=10,000\\Q_{0}=-6538exp(-0.26*0)+C\\C=10,000+6538=16538

Then, we reorganize the equation and we replace t for 17 hours, in order to determine the quantity of contaminant at that time:

Q_{t} =-6538exp(-0.26t)+16538\\Q_{17} =-6538exp(-0.26*17)+16538\\Q_{17} =16460 gallons

3 0
3 years ago
Will give brainliest to actual answer
Keith_Richards [23]

in    |   out

100 |  51

4    |  3

 6   |  4

30  |  16

60  |  31

rule: y = x/2+1

Please give me Brainly now

3 0
3 years ago
Read 2 more answers
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