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3 years ago

The vertices of the triangle are given. determine whether the triangle is an acute traignel, obtuse triangle

1 answer:

8 0

What are the angles?

if all of them are below 90 degrees, it is acute.

if one angle is 90 degress, it is right

if one angle is more than 90 degrees, it is obtuse

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Use the periodic compound interest formula to solve.

77julia77 [94]

Answer:

$15,539.67

Step-by-step explanation:

Compound Interest Formula

$\large \text{$ \sf A=P\left(1+\frac{r}{n}\right)^{nt} $}$

where:

A = final amount
P = principal amount
r = interest rate (in decimal form)
n = number of times interest applied per time period
t = number of time periods elapsed

Given:

P = $11,000
r = 5.8% = 0.058
n = 4 (quarterly)
t = 6 years

Substitute the given values into the formula and solve for A:

$\implies \sf A=11000\left(1+\frac{0.058}{4}\right)^{(4 \times 6)}$

$\implies \sf A=11000(1.0145)^{24}$

$\implies \sf A=15539.67451...$

Therefore, the value of the investment after 6 years will be $15,539.67 to the nearest cent.

3 0

2 years ago

Find the measure of A.<br> A. 50<br> B. 70<br> C. 100<br> D. 90

dlinn [17]

Answer:

Step-by-step explanation:

I don't know how to eliminate the wrong answers.

Two line segments which have one end at a diameter and the other end meeting at a common point, make a 90 degree angle.

A is made that way, so A is 90 degrees.

8 0

3 years ago

I need help with this question.

Alborosie

Answer:

2116

Step-by-step explanation:

hope this helps :)

5 0

3 years ago

Complete the statement with equal to greater than or less than 5/5 * 2 3/4

Westkost [7]

5/5*2 3/4 > 2 3/4

hope this helps :)

3 0

3 years ago

For a function g(x), the difference quotient is StartFraction 6 Superscript x + h minus 3 Baseline minus 6 Superscript x + 3 Bas

kobusy [5.1K]

Answer:

The average rate of change in that interval is 1.99

Step-by-step explanation:

Here we have that the difference quotient for g(x) is:

$\frac{6^{x + h} - 3 - 6^x + 3}{h}$

Remember that for a general function f(x), the difference quotient is:

$\frac{f(x + h) - f(x)}{h}$

So if we look at the difference quotient for g(x), we can conclude that:

$g(x) = 6^x - 3$

Also remember that the average rate of change in an interval (a, b) is just:

$\frac{g(b) - g(a)}{b - a}$

So here we want the average rate of change of g(x) in the interval from x = -2 to x = 1, this is:

$R = \frac{(6^1 - 3) - (6^{-2} - 3)}{1 - (-2)} = \frac{6 - 6^{-2}}{3} = 1.99$

The average rate of change in that interval is 1.99

8 0

3 years ago