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3 years ago

Helppp guys i really don't get it

Mathematics

1 answer:

AysviL [449]3 years ago

8 0

9514 1404 393

Answer:

(b) ... confirm ∠C≅∠E

Step-by-step explanation:

The first step is to read and understand the problem statement. It is asking for a way to prove ΔABC ~ ΔADE by AA similarity. That means you want to show any two of the three ...

∠A≅∠A
∠B≅∠D
∠C≅∠E

For this purpose, lengths of line segments are irrelevant (eliminating the last two answer choices). The fact that ∠A≅∠A is given, so you only need to find an answer choice that will show one of the last two angle congruences.

Obviously, showing ∠B≅∠E (choice A) is not relevant to the problem.

The only answer choice that is relevant to the question is the second one, showing ∠C≅∠E.

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3 years ago

2) Determine if the following lines are or are not parallel.

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3 years ago

find an equation of the tangent plane to the given parametric surface at the specified point. x = u v, y = 2u2, z = u − v; (2, 2

Alexxandr [17]

The surface is parameterized by

$\vec s(u,v) = x(u, v) \, \vec\imath + y(u, v) \, \vec\jmath + z(u, v)) \, \vec k$

and the normal to the surface is given by the cross product of the partial derivatives of $\vec s$ :

$\vec n = \dfrac{\partial \vec s}{\partial u} \times \dfrac{\partial \vec s}{\partial v}$

It looks like you're given

$\begin{cases}x(u, v) = u + v\\y(u, v) = 2u^2\\z(u, v) = u - v\end{cases}$

Then the normal vector is

$\vec n = \left(\vec\imath + 4u \, \vec\jmath + \vec k\right) \times \left(\vec \imath - \vec k\right) = -4u\,\vec\imath + 2 \,\vec\jmath - 4u\,\vec k$

Now, the point (2, 2, 0) corresponds to u and v such that

$\begin{cases}u + v = 2\\2u^2 = 2\\u - v = 0\end{cases}$

and solving gives $u = v = 1$ , so the normal vector at the point we care about is

$\vec n = -4\,\vec\imath+2\,\vec\jmath-4\,\vec k$

Then the equation of the tangent plane is

$\left(-4\,\vec\imath + 2\,\vec\jmath - 4\,\vec k\right) \cdot \left((x-2)\,\vec\imath + (y-2)\,\vec\jmath + (z-0)\,\vec k\right) = 0$

$-4(x-2) + 2(y-2) - 4z = 0$

$\boxed{2x - y + 2z = 2}$

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2 years ago

4. What inequality represents the amount of hours the student can work each month? Make a graph.

liubo4ka [24]

Answer:

View Image

Step-by-step explanation:

Solve for either of the variable. I solved for c because it looked easier.

Set c = 0 to solve for the x-intercept so that you can graph it. c is just your y-value in this case and m is your x-value.

I got m=90 which means it crosses the x-axis at 90. I also know it cross the y-axis at 90 because c = 90 - m is in the form of slope-intercept formula. The 90 in there is the y-intercept.

The sign is a > so it's a dotted line shaded above the graph.

Same process as part 4. Set c=0 to find the x-intercept. I got m=100 which means it cross the x-axis at 100.

The y-intercept is in the equation itself c = 80 - 4/5m. The y-intercept is 80.

The sign is a ≥ so it's a solid line shaded above the graph.

3 0

3 years ago

Helppp guys i really don't get it​

Helppp guys i really don't get it