Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)
Given : y = -25 and x = -5
We can notice that if we Multiply 'x' with 5 we get 'y'
That is (-5) × 5 = -25
⇒ x multiplied by 5 = y
(a) The Equation that relates x and y is 5x = y
(b) We found that the Equation of this Direct variation is : 5x = y
The Question is to find the value of y when x = 3
The Value of y at x = 3 can be found by simply substituting x = 3 in the equation we found.
⇒ y = 5x
⇒ y = 5 × 3
⇒ y = 15
So, the Value of y when x = 3 is 15
Answer:
Step-by-step explanation:
- (3⁴)⁻² * (3⁵)³ =
- 3⁴⁽⁻²⁾*3⁵⁽³⁾ =
- 3⁻⁸*3¹⁵ =
- 3⁻⁸⁺¹⁵ =
- 3⁷
Correct option is B. 3⁷
Given:
The length of the marathon is L= 46,145 yards.
The length covered by terrence is d = 23,561 yrads.
The objective is to find the remaining distance need to cover by terrence.
To calculate the remaining distance, we will use the relation,

On plugging the values in the above relation, we get,

Hence, Terrence needs to run about 23000 yards.
x is 280........................