What is the anwser to 8h times $9/h and what is the ratio units

Solve the equation on the interval [0,2pi] 5sec(x)+7=-3

vovangra [49]

Answer:

Hello,

$x\in \bigg\{\dfrac{2\pi}{3} ,\dfrac{4\pi}{3}\bigg\}\\$

Step-by-step explanation:

$5*sec(x)+7=-3\\\\sec(x)=\dfrac{-10}{5} \\\\\dfrac{1}{cos(x)} =-2\\\\cos(x)=-\dfrac{1}{2} \\\\x=120^o\ or\ x=240^o\\$

8 0

2 years ago

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PLEASE HELP! ANSWER NEEDED ASAP!!! <img src="https://tex.z-dn.net/?f=%5Cint%5Climits%20x%5E3%20%28x-%20%5Csqrt%7Bx%7D%20%2B2

77julia77 [94]

$fx ^{5} d - fx ^{4 \sqrt{x + 2d} } \\$

3 0

3 years ago

Solve the system by substitution. x = -2y + 5 -8x – 3y = -1

mote1985 [20]

Jejdjejjejejejejejjejejeejjeje

3 0

3 years ago

A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random

Yuliya22 [10]

Answer:

b) independent samples t-test

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

Step-by-step explanation:

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2\neq 0$

Our notation on this case :

$n_1 =5$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

We can calculate the mean and deviation for eaach group with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_1 =5.92$ represent the sample mean for the group 1

$\bar X_2 =5.74$ represent the sample mean for the group 2

$s_1=1.88$ represent the sample standard deviation for group 1

$s_2=1.81$ represent the sample standard deviation for group 2

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}$

And now we can calculate the statistic:

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

The degrees of freedom are given by:

$df=5+5-2=8$

And now we can calculate the p value using the altenative hypothesis:

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

7 0

3 years ago

In math :

gizmo_the_mogwai [7]

1)how calendar relate to math?
The numbers.
You need to be able to know the date, how many days till this, so you add, how many more till this, add again, and more.
2) how cooking relate to math?
Measurements.
For example:
2 eggs
1/4 cup of flour
and
2/4 cup of milk.
You need to be able to calculate and know your measurements. Which math helps you with/
3)how time / weather /money relate to math?
Time: Numbers.
Weather: Patterns and time.
Money: Lots and lots of math.
Adding subtracting dividing multiplying and so much more.

8 0

3 years ago

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