Your question is difficult to understand, that is why I am going to edit your question as follow:
<u>Edited Question:</u>
Cone A and B both have a volume of 48π Cubic units but have different dimensions. Cone A has a radius=6 units and a height=4 units.
Find the one possible radius and height for cone B be to have the same volume as cone A.
Answer:
Radius of cone B= 6units
Height of cone B=units
Step-by-step explanation:
As we know the formula for the volume of a cone is
If volume of A and Volume B is given as same, thus
comparing equations above, we get
Thus, Radius of cone A=6units
and
Height of cone B= 4units
Y=10x+10
add the like terms together
Answer:
f(x) = - 8
Explanation:
The given function is
f(x) =2x^2 -4x -6
The first step is to find the derivative of the function. Recall, if
y = ax^b
y' = abx^(b - 1)
Thus,
f'(x) = 4x - 4
We would equate f'(x) to zero and solve for x. We have
4x - 4 = 0
4x = 4
x = 4/4
x = 1
We would substitute x = 1 into the original function and solve for f(x) or y. It becomes
f(1) =2(1)^2 -4(1) - 6 = 2 - 4 - 6
f(1) = - 8
Thus, the minimum value is f(x) = - 8
You can multiply the number by itself that’s what it means
Answer:
I think is b
Step-by-step explanation:
that make more sentences