ou invested 7000 between two accounts paying 4% and 9% annual interest, respectively. If the total interest earned for the year
was $430 how much was invested at each rate? $ nothing was invested at and $ nothing was invested at
1 answer:
9514 1404 393
Answer:
Step-by-step explanation:
Let x represent the amount invested at 9%. Then 7000-x was invested at 4% and the interest earned was ...
9%·x +4%(7000-x) = 430
5%·x +280 = 430 . . . . . . . . . simplify
0.05x = 150 . . . . . . . . . . . subtract 280
x = 3000 . . . . . . . . . . divide by 0.05
$3000 was invested at 9%; $4000 was invested at 4%.
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Answer:
Step-by-step explanation:
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They are both correct it's just that the say it differently 8/4 IS 2 so yea. I'm a middle schooler.
Answer:
length = 8; width = 3
perimeter = 22
area = 24
Step-by-step explanation:
L(- 1,3), M(2,3)
LM = |-1 - 2| = 3
M(2,3), N(2, - 5)
MN = |-5 - 3| = 8
length = 8; width = 3
perimeter = 2(L + W) = 2(8 + 3) = 22
area = LW = 8 × 3 = 24
Slope =1/2x hopefully this helps
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