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ruslelena [56]
2 years ago
13

Children. The

Mathematics
1 answer:
AVprozaik [17]2 years ago
6 0

Answer:

C!

15a + 10c = 2350

a + c = 180

Step-by-step explanation:

$15 x number of adults + $10 x number of kids = $2350

Number of adults + number of children = number of seats

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I need help whats 100 plus 20
grigory [225]

Answer: 120

Step-by-step explanation:

6 0
2 years ago
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Find the equivalent to x^7
MrMuchimi
1/x^-7

It would look more like       1
                                        ------
                                             -7 (as an exponent)
                                          x
3 0
3 years ago
Kinda need help anything helps
katovenus [111]
First you have to find the slope with the equation y2 - y1 / x2 - x1 , then once you have found the slope (slope = -2) you simply plug it into the point slope formula. y-0 = -2(x-5) solving it algebraically you should arrive at Y=-2x+10. (the 5 and 0 were plugged in are two of the X and Y points of the line which is why we plugged them into the X and Y values of the equation)
6 0
3 years ago
A 12 oz bottle of shampoo last 16 weeks. How long would you expect an 18 oz bottle to last
jenyasd209 [6]
If a 12 oz bottle of shampoo lasted for 16 weeks, we have a ratio of 12:16 which can be shortened to 3:4.

Now if we have 18 oz bottle we know that it's 1/2 more than 12 oz bottle, so the ratio will be also 1/2 more. So if it was 12:16, the new ratio will be:

12 + (1/2 * 12) : 16 + (1/2 * 16)
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It means that 18 oz bottle should last for 24 weeks. Of course the ratio has to stay the same in its lowest form in both situations and as 18:24 can be shortened to 3:4, it proves it's correct :)
3 0
3 years ago
A computer training institute has 625 students that are paying a course fee of $400. Their research shows that for every $20 red
Anastasy [175]
1.
If no changes are made, the school has a revenue of :

625*400$/student=250,000$

2.
Assume that the school decides to reduce n*20$.

This means that there will be an increase of 50n students.

Thus there are 625 + 50n students, each paying 400-20n dollars.

The revenue is: 

(625 + 50n)*(400-20n)=12.5(50+n)*20(20-n)=250(n+50)(20-n)

3.

check the options that we have, 

a fee of $380 means that n=1, thus 

250(n+50)(20-n)=250(1+50)(20-1)=242,250   ($)


a fee of $320 means that n=4, thus

 250(n+50)(20-n)=250(4+50)(20-4)=216,000    ($)


the other options cannot be considered since neither 400-275, nor 400-325 are multiples of 20.

Conclusion, neither of the possible choices should be applied, since they will reduce the revenue.
6 0
3 years ago
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