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4 years ago

Alex’s paycheck for the last two weeks totaled $239.64. He owes the cell phone company $45.87. How much money does he have left?

Mathematics

2 answers:

kolezko [41]4 years ago

5 0

The answer is 193.77 because 239.64-45.87 is 193.77.

Hitman42 [59]4 years ago

4 0

You basically take 45.87 and subtract it from the total of 239.34
239.34
-45.87
your total left would be $193.77

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I need help with question a and b

DaniilM [7]

Solving for part A

$f(x) = x^{2} \;\;and\;\; g(x) = \frac{1}{x^{3}} \\\\f(g(x)) = (\frac{1}{x^{3}})^{2} =\frac{1}{x^{6}}$

Domain of composition: x ≠ 0 i.e. Domain is the set of "Real numbers excluding number 0".

Solving for part B

$f(x) = \frac{x}{x-2}\;\;and\;\;g(x) =\frac{3}{x} \\\\f(g(x))=\frac{\frac{3}{x}}{\frac{3}{x}-2}=\frac{\frac{3}{x}}{\frac{3-2x}{x}} =\frac{3}{3-2x}\\\\ Domain:\;3-2x\neq 0 \;\;OR\;\;x\neq \frac{3}{2}$

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4 years ago

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IceJOKER [234]

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3 years ago

Read 2 more answers

The water from a fire hose follows a path described by y equals 2.0 plus 0.9 x minus 0.10 x squared (units are in meters). If

Alecsey [184]

Answer:

The resultant velocity is 12.21 m/s.

Step-by-step explanation:

We are given that the water from a fire hose follows a path described by y equals 2.0 plus 0.9 x minus 0.10 x squared (units are in meters).

Also, v Subscript x is constant at 10.0 m/s.

The water from a fire hose follows a path described by the following equation below;

$y=2.0 + 0.9x-0.10x^{2}$

The velocity of the $x$ component is constant at = $v_x=10.0 \text{ m/s}$

and the point at which resultant velocity has to be calculated is (9.0,2.0).

Let the velocity of x and y component be represented as;

$v_x=\frac{dx}{dt} \text{ and } v_y=\frac{dy}{dt}$

Now, differentiating the above equation with respect to t, we get;

$y=2.0 + 0.9x-0.10x^{2}$

$\frac{dy}{dt} =0 + 0.9\frac{dx}{dt} -(0.10\times 2)\frac{dx}{dt}$

$\frac{dy}{dt} = 0.9\frac{dx}{dt} -0.2\frac{dx}{dt}$

$v_y = 0.9v_x -0.2v_x$

$v_y = 0.7v_x$

Now, putting $v_x=10.0 \text{ m/s}$ in the above equation;

$v_y = 0.7 \times 10.0$ = 7 m/s

Now, the resultant velocity is given by = $v=\sqrt{v_x^{2}+v_y^{2} }$

$v=\sqrt{10^{2}+7^{2} }$

= $\sqrt{149}$ = 12.21 m/s

5 0

3 years ago

Help me please! These are due today.

IrinaVladis [17]

Answer:

${x}^{2} + 3x$

Step-by-step explanation:

Area of shaded region = Area of external rectangle - Area of internal rectangle

$= 4x(x + 2) - x(3x + 5) \\ = 4 {x}^{2} + 8x - 3 {x}^{2} - 5x \\ = 4 {x}^{2} - 3 {x}^{2} + 8x - 5x \\ = {x}^{2} + 3x \\$

Let the width of the rectangle be x inches.

Therefore, length of the rectangle = (x + 3) inches

Area of rectangle

$=(x + 3)\times x\\=x^2 + 3x\\$

Width of rectangle = 4 inches

Length of rectangle = 4 + 3 = 7 inches

Area of rectangle = 7*4 = 28 square inches.

6 0

3 years ago

When writing 3.7272727272... as a ratio of integers, what is the common ratio?

Law Incorporation [45]

The answer is: "41 / 11 " ; or, write as: " 41 : 11 " .
__________________________________________________________
Explanation:
__________________________________________________________
72/99 = (72÷9) / (99÷9) = 8/ 11 .

So, 3.727272727272... = "3 $\frac{8}{11}$ " .

→ "3 $\frac{8}{11}$ " = [(11 *3) + 8] / 11 = (33 + 8) / 11 = 41 / 11 .
__________________________________________________________
"41 / 11" cannot be simplified any further; so the answer is:
__________________________________________________________
"41 / 11 " ; or, write as: " 41 : 11 " .
__________________________________________________________

5 0

3 years ago