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drek231 [11]
2 years ago
9

Match each equation to its solution​

Mathematics
2 answers:
Finger [1]2 years ago
5 0

Answer:

1st answer: -8

2nd answer: -5.2

3rd answer: 28.8

4th answer: 4

AleksandrR [38]2 years ago
5 0

Answer:

x/2=-4_______ -8

-5x=26_______ -5.2

x/-7.2=-4________28.8

3  

__  =6________4

2  x

Step-by-step explanation:

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If 72 = 12x, what does x equal?
CaHeK987 [17]

Answer:

x=6

Step-by-step explanation:

So, x is our unknown variable. An so you have to ask yourself, what times 12= 72? The answer would be 6, because 12x6=72

The proper way to do it, would be to divide 12/12 so you isolate the variable, and what you do to one side, you do to the other, so divide 72 by 12 and you get 6! Hope this helps!

6 0
2 years ago
The formula for the volume of this rectangular prism is:<br><br> V = 5x3 + 29x2 + 34x – 8
mel-nik [20]

Answer:

-199

Step-by-step explanation:

7 0
3 years ago
1,868 to the nearest hundred
Citrus2011 [14]

Answer: 1,900

Step-by-step explanation:

You would round up to 1,900 because in the tens place is a 6 and when you have a number greater than or equal to 5 you round up. Hope this helps!

7 0
2 years ago
coin $a$ is flipped three times and coin $b$ is flipped four times. what is the probability that the number of heads obtained fr
ivolga24 [154]

The probability that the number of heads obtained from flipping the two fair coins is the same is 35/128.

Probability:

Probability means the fraction of favorable outcome and the total number of outcomes.

So it can be written as,

Probability = Favorable outcomes / Total outcomes

Given,

The coin a is flipped three times and coin b is flipped four times.

Here we need to find the probability that the number of heads obtained from flipping the two fair coins is the same.

We know that,

There are 4 ways that the same number of heads will be obtained;

0, 1, 2, or 3 heads.

The probability of both getting 0 heads is

$\left(\frac12\right)^3{3\choose0}\left(\frac12\right)^4{4\choose0}=\frac1{128}$

Probability of getting 1 head,

$\left(\frac12\right)^3{3\choose1}\left(\frac12\right)^4{4\choose1}=\frac{12}{128}$

Probability of getting 2 heads is,

$\left(\frac12\right)^3{3\choose2}\left(\frac12\right)^4{4\choose2}=\frac{18}{128}$

And the probability of getting 3 heads is,

$\left(\frac12\right)^3{3\choose3}\left(\frac12\right)^4{4\choose3}=\frac{4}{128}$

Therefore, the probability that the number of heads obtained from flipping the two fair coins is the same is,

=> (1/128) + (12/128) + (18/128) + (4/128)

=> 35/128.

To know more about probability here

brainly.com/question/14210034

#SPJ4

4 0
1 year ago
Plzz help/giving brainlest plzzzzzz
Katena32 [7]

Answer:

the first one is 86in

Step-by-step explanation:

im working on the 2nd one rn ill get the answrr to u as fast as i can

3 0
3 years ago
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