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2 years ago

Evaluate the expression. (6 − 3)!

Mathematics

2 answers:

olga55 [171]2 years ago

3 0

Answer:

Step-by-step explanation:

If this isn't a trick question then the answer is 3.

scZoUnD [109]2 years ago

3 0

Answer is 6, u do what’s in the parenthesis first or not idk, but I got 6 and that’s the calculators work so... ‍♀️‍♀️

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What is the inverse of Y=-5x-7

Pepsi [2]

Answer:y = - 5x - 7

Step-by-step explanation:The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

here m = - 5 and b = - 7, hence

y = - 5x - 7 ← equation of line

7 0

2 years ago

Which series of transformations maps △ABC to △A′B′C′?

denis-greek [22]

Answer:

Step-by-step explanation:

If you translate left one unit, then reflect across the x axis, you get the ending figure

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2 years ago

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Please answer #1 for me only ! What is my Y for #1 , don't forget to graph !

mart [117]

The table and the graph is shown in the following picture

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2 years ago

What is the value of x? Enter your answer in the box. _____ units

krek1111 [17]

Answer:

x=28

Step-by-step explanation:

We can use similar triangles and proportions to solve this problem. Put the side of the small triangle over the same side of the larger triangle.

x 42

---------- = ----------

x+10 42+15

Simplify

x 42

---------- = ----------

x+10 57

Using cross products

57x = 42 (x+10)

Distribute

57x = 42x+420

Subtract 42x from each side

57x-42x = 42x-42x +420

15x = 420

Divide each side by 15

15x/15 = 420/15

x=28

6 0

2 years ago

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Find the inverse Laplace transform f(t) of the function F(s). Write uc for the Heaviside function that turns on at c, not uc(t).

zzz [600]

Answer:

F(t) $=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}$

Step-by-step explanation:

We have given $F(S)=\frac{7e^{-7s}}{s^2-49}$

Now $F(S)=e^{-7s}G(s)$

Here $G(S)=\frac{7}{S^2-49}$

Now first find the Laplace inverse of G(S)

Using partial fraction

$\frac{7}{(s+7)(s-7)}=\frac{A}{(S+7)}+\frac{B}{S-7}$

$7=A(S-7)+B(S+7)$

On comparing the coefficient

$A=\frac{1}{2}$ and $B=\frac{-1}{2}$

On putting the value of A and B

$G(S)=\frac{-1}{2(S+7)}+\frac{1}{2(S+7)}$

Taking inverse Laplace

$G(t)=\frac{-1}{2}e^{7t}+\frac{1}{2}e^{-7t}$

Now in G(s) there is onether term $e^{-7s}$

So F(t) $=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}$

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2 years ago