Solution
The reflection is a rigid transformation. This does not affect the length of a line segment.
Therefore, the line segments are equal.
Hence, LM = L'M'
Thank you. :)
I think you meant to say

(as opposed to <em>x</em> approaching 2)
Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

1) A translation 2 units right
2) A reflection over the x-axis
The diameter is 10:
To do this we must use the distance formula:
Distance =√(x2−x1)^2+(y2−y1)^2
So, if we substitute in our values for the origin and endpoint (origin is 1 values, endpoint is 2)
D=✓(-4-0)^2+(-3-0)^2
Simplified, this is
D=✓16+9
D=✓25
D=5
so, the distance from the center of the crcle to the endpoint is 5 (making the radius)
multiply by two, and the diameter of the circle is 10 :)
Answer:
s = 
Step-by-step explanation:
Given
v² = u² + 2as ( subtract u² from both sides )
v² - u² = 2as ( divide both sides by 2a )
= s
Given
v² = u² + 2as ( subtract 2as from both sides )
v² - 2as = u² ( take the square root of both sides )
±
= u