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DochEvi [55]
3 years ago
13

What is the slope of the line that passes through the points (4, -6) and (-5, 9)

Mathematics
2 answers:
In-s [12.5K]3 years ago
7 0
Answer choice D. I used the slope formula. 
Flauer [41]3 years ago
6 0
Slope = (9+6)/(-5-4) = 15/-9 = -5/3

answer

A. -5/3 fist choice
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Lily graphs segment LM. Then, she reflects the segment across the y-axis. Which statement compares the lengths of the segment LM
Free_Kalibri [48]

Solution

The reflection is a rigid transformation. This does not affect the length of a line segment.

Therefore, the line segments are equal.

Hence, LM = L'M'

Thank you. :)


8 0
2 years ago
Read 2 more answers
Lim t^4 - 6 / 2t^2 - 3t + 7
Harman [31]

I think you meant to say

\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}

(as opposed to <em>x</em> approaching 2)

Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}

6 0
2 years ago
3. (x,y) → (x + 2,y) → (x, y)
Llana [10]

1) A translation 2 units right

2) A reflection over the x-axis

4 0
2 years ago
The center of a circle is at the origin. and endpoint of a diameter of the circle is at (-3, -4. how long is the diameter of the
Aleks [24]
The diameter is 10:

To do this we must use the distance formula:

Distance =√(x2−x1)^2+(y2−y1)^2

So, if we substitute in our values for the origin and endpoint (origin is 1 values, endpoint is 2)

D=✓(-4-0)^2+(-3-0)^2

Simplified, this is

D=✓16+9
D=✓25
D=5

so, the distance from the center of the crcle to the endpoint is 5 (making the radius)

multiply by two, and the diameter of the circle is 10 :)
4 0
2 years ago
Make s, u subject of the formula<br><img src="https://tex.z-dn.net/?f=v%5E%7B2%7D%20%3D%20u%20%7B%7D%5E%7B2%7D%20%2B%202as" id="
Romashka [77]

Answer:

s = \frac{v^2-u^2}{2a}

Step-by-step explanation:

Given

v² = u² + 2as ( subtract u² from both sides )

v² - u² = 2as ( divide both sides by 2a )

\frac{v^2-u^2}{2a} = s

Given

v² = u² + 2as ( subtract 2as from both sides )

v² - 2as = u² ( take the square root of both sides )

± \sqrt{v^2-2as} = u

6 0
3 years ago
Read 2 more answers
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