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Otrada [13]
3 years ago
9

The one with the ? I need the answer

Mathematics
1 answer:
koban [17]3 years ago
5 0
Subtract 17, 8, and 4 from the 30 days in September. 
30-17=13
13-8=5
5-4=1
You might be interested in
If y is directly proportional with x and y = 36 when x = 30, what is the value of y when x = 40?
vivado [14]

Answer:

y = 48

Step-by-step explanation:

given y is directly proportional to x then the equation connecting them is

y = kx ← k is the constant of proportionality

To find k use the condition y = 36 when x = 30

k = \frac{y}{x} = \frac{36}{30} = \frac{6}{5}

y = \frac{6}{5} x ← equation of proportionality

When x = 40 then

y = \frac{6}{5} × 40 = 48


3 0
3 years ago
Please help I’m so confused
Natalka [10]

Answer:

SA = 742

Step-by-step explanation:

H*L + H*W + L*W = SA

(8 x 6) x 2= 96

(22 x 6) x 2 = 264

(8 x 22) x 2 = 352

96 + 264 + 352 = 742

7 0
3 years ago
Read 2 more answers
What is the standard form of (7 - 51)(2 + 3)?
patriot [66]

AnswerAnd Step-by-step explanation:

7-5x2+3

x= times or multiplied

3 0
3 years ago
Read 2 more answers
What the answer y-8=-2 (x-7)
Kamila [148]
The answer is:
 Solve for y in the first equation
y=−5<span>
y=8−<span>x
</span></span>
<span>Replace all occurrences of y with the solution found by solving the last equation for y. In this case, the value substituted is <span>−5</span></span><span>y=−5</span><span><span>(−5)</span>=8−<span>x
</span></span>
Remove parentheses.<span>y=−5</span><span>−5=8−<span>x
</span></span>
Solve for x in the second equation.<span>y=−5</span>
<span>x=13</span>
The answer is <span>(13,−5<span>)            Please mark as Brainliest
</span></span>



5 0
3 years ago
A population of values has a normal distribution with μ = 247 and σ = 62.2. You intend to draw a random sample of size n = 16. (
nadya68 [22]

Answer:

a) z = \frac{295.2-247}{62.2}=0.772

And using the normal distribution table or excel we got:

P(Z>0.772) = 1-P(Z

b) z = \frac{295.5 -247}{\frac{62.2}{\sqrt{16}}}= 3.119

And we can use the normal standard table or excel in order to find the probability and we got:

P(z>3.119) =1-P(Z

Step-by-step explanation:

For this case we know that the random variable of interest is normally distributed with the following parameters:

X \sim N (\mu = 247, \sigma =62.2)

Part a

We want to find this probability:

P(X>295.2)

And we can use the z score formula given by:

z = \frac{X-\mu}{\sigma}

Replacing we got:

z = \frac{295.2-247}{62.2}=0.772

And using the normal distribution table or excel we got:

P(Z>0.772) = 1-P(Z

Part b

We select a random sample of size n = 16 and we try to find this probability:

P(\bar X >295.2)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{295.5 -247}{\frac{62.2}{\sqrt{16}}}= 3.119

And we can use the normal standard table or excel in order to find the probability and we got:

P(z>3.119) =1-P(Z

8 0
3 years ago
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