All categories

4 years ago

Make x the subject of the formula (help again)I'm really bad at these xk-w=y

Mathematics

2 answers:

7nadin3 [17]4 years ago

5 0

Answer:

x = (y+w)/k

Step-by-step explanation:

xk-w=y

Add w to each side

xk-w+w=y+w

xk = y+w

Divide each side by k

xk/k = (y+w)/k

x = (y+w)/k

alexandr1967 [171]4 years ago

3 0

Answer:

x= $\frac{y+w}{k}$

Step-by-step explanation:

Have a nice day

You might be interested in

What is an equivalent fraction of 2

Sati [7]

Answer:

$\frac{2}{1}$

Step-by-step explanation:

$\frac{2}{1} = 2$

If a fractions denominator is a one that means the fraction is equal to the numerators whole number in this case we have 2/1 since the denominator is a 1 that means the whole fraction is equal to 2 because the numerator is 2.

Hope this helps.

6 0

3 years ago

if the first two statements are true, is the third statement true? 1. all dogs like walks. 2. bandit doesn't like walks. 3. band

Strike441 [17]

If the first two statements are true, then the third statement:

"Bandit is not a dog"

Is true.

<h3>if the first two statements are true, is the third statement true?</h3>

The first statement is:

P = "All dogs like walks"

We assume that this is true, so, if X is a dog, X likes walks.

The second statement is:

Q = "Bandit doesn't like walks"

From this, we only can conclude that Bandit doesn't like walks.

And all dogs like walks, so if Bandit were a dog, he would like walks, but because he does not like walks, we can conclude that Bandit is not a dog.

From that, the third statement:

K = "Bandit is not a dog"

Is true.

So we write that as a conditional statement:

If P and Q ⇒ K

<em>"if all dogs like walks, and Bandit doesn't like walks, then bandit is not a dog".</em>

If you want to learn more about conditional statements:

brainly.com/question/11073037

#SPJ1

3 0

2 years ago

A new sales training program has been instituted at a rent-to-own company. Prior to the training, 10 employees were tested on th

Lunna [17]

Answer:

C. H0: µD = 0, HA: µD <0

Step-by-step explanation:

We assume that the paired sample data are simple random samples and that the differences have a distribution that is approximately normal. So for this case is better apply a paired t test.

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.

Let put some notation

x=test value for pretest , y = test value for posttest

x: 66, 94, 87, 84, 76, 88

y: 75, 100, 93, 85, 75, 90

The system of hypothesis for this case are:

Null hypothesis: $\mu_D \geq 0$

Alternative hypothesis: $\mu_D < 0$

Because the difference D is defined as Pretest-Postest. And we want to see if the postets score is higher than the pretest with th training.

The first step is calculate the difference $d_i=x_i-y_i$ and we obtain this:

d: -9, -6, -6, -1, 1, -2

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{-23}{6}=-3.833$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =3.763$

The 4 step is calculate the statistic given by :

$t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-3.833 -0}{\frac{3.763}{\sqrt{6}}}=-2.494$

The next step is calculate the degrees of freedom given by:

$df=n-1=6-1=5$

Now we can calculate the p value, since we have a left tailed test the p value is given by:

$p_v =P(t_{(5)}$

The p value is lower than the significance level assumed $\alpha=0.05$ , so then we can conclude that we can reject the null hypothesis. So we can say that the differences between Pretest and Posttest $\mu_{pretest}-\mu_{postest}$ are less than 0.