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3 years ago

If f(x)=3x^5-2x^3+1, then f(-1)=?

Mathematics

2 answers:

Sliva [168]3 years ago

8 0

Answer:

f(-1) =0

Step-by-step explanation:

f(x)=3x^5-2x^3+1

Let x = -1

f(-1) = 3(-1)^5 -2(-1)^3 +1

= 3(-1) -2(-1)+1

=-3 +2+1

Ksivusya [100]3 years ago

4 0

Answer:

f(-1)=0

Step-by-step explanation:

f(x)=3x^5-2x^3+1

well, all you have to do is to replace x with -1.

f(-1)=3·(-1)^5-2·(-1)^3+1

f(-1)=3·(-1)-2·(-1)+1

f(-1)=-3+2+1

f(-1)=-3+3=0

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2 years ago

A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch

ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

$P$ = a person passes the security system

$H$ = a person is a security hazard

Given:

$P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01$

Then,

$P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\$

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: $P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The value of P (P) is:

$P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412$

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

$P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1$

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

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3 years ago

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Answer:

0 ≤ m ≤ 7
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The y-intercept is the value when m=0. It is the length of the fish at the start of the study.

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2 years ago

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3 years ago

The circumference of a circle is given by the formula C = 2 π r . Find r if the circumference is 352 meters and π is 227 .

icang [17]

Answer:

The radius of the circle is 56 meters.

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Now we have to simplify.

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