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vodomira [7]
3 years ago
7

Consider three events A, B and C with following properties.

Mathematics
1 answer:
lisov135 [29]3 years ago
5 0
By the inclusion/exclusion principle,

\mathbb P(D)=\mathbb P(A\cup B\cup C)
\mathbb P(D)=\mathbb P(A)+\mathbb P(B)+\mathbb P(C)-\bigg(\mathbb P(A\cap B)+\mathbb P(A\cap C)+\mathbb P(B\cap C)\bigg)+\mathbb P(A\cap B\cap C)
\mathbb P(D)=\dfrac14+\dfrac16+\dfrac14-\dfrac39+\dfrac1{13}
\mathbb P(D)=\dfrac{16}{39}\neq1

So the union of A, B, and C does not constitute the entire sample space.
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It took the high school hockey team 5h to travel to a tournament in Thunder Bay. They travelled by bus and plane a total distanc
mote1985 [20]
Entire distance = 1,320
Entire time = 5 hours

bus avg = 40 km/h
plane avg = 600 km/h

Working this by trial and error
1 hour bus 4 hour plane = 40 + 2,400 = 2,800 distance (too high)
2 hour bus 3 hour plane = 80 + 1,800 = 1,880 distance (too high)
3 hour bus 2 hour plane = 120 + 1,200 = 1,320 distance (Correct!!)

So, they traveled 3 hours by bus and 2 hours by plane
(yes, you had the right answer).

8 0
3 years ago
Question 4 (0.5 points)
photoshop1234 [79]
It has to be b because none of the others are correct.
3 0
3 years ago
50 points! I understand A. and B. but I would really appreciate help with C.
FromTheMoon [43]

Answer:

51.72\text{ cells per hour}

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

C)

So, we are given that the quadratic curve of the trend is the function:

P(t)=6.10t^2-9.28t+16.43

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]

Expand:

P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]

Differentiate. Use the power rule:

P'(t)=6.10(2t)-9.28(1)

Simplify:

P'(t)=12.20t-9.28

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

P'(5)=12.20(5)-9.28

Multiply:

P'(5)=61-9.28

Subtract:

P'(5)=51.72

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

7 0
3 years ago
What’s the inverse of 2(x-2)^2 = 8(7+y)
Anettt [7]

Answer:

y= (x-2)^2/4-7

Step-by-step explanation:

5 0
3 years ago
The ratio of boys to girls in a school is 4:5. How many boys are in the school if there are 720 students.
scZoUnD [109]

Answer: 320 boys

Step-by-step explanation: you would first take the total number (720) and divide it by the total number shown in the ratio (5+4=9)

720/9= 80

You would then take 80 and multiply it by 4 because that is the number representing the boys

80*4= 320

7 0
3 years ago
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