Question

PLEASE HELP, Don’t know how to solve.

Answer 1

Let's just put it in vertex form so we know what it is

y=x^2+2x+1

y-1=x^2+2x

y-1+1=x^2+2x+1

y=(x+1)^2

So the vertex is (-1, 0), and since the coefficient is 1 is positive this vertex is the absolute minimum for the parabola.

So plot points for x={-3,-2,0,1} to get

(-3, 4),(-2, 1),(-1, 0),(0, 1),(1, 4)