Y = mx + b
slope(m) = 3/2
(5,9)...x = 5 and y = 9
now we sub and find b, the y int
9 = 3/2(5) + b
9 = 15/2 + b
9 - 15/2 = b
18/2 - 15/2 = b
3/2 = b
so ur equation is : y = 3/2x + 3/2.........(3,a)....so x = 3
y = 3/2(3) + 3/2
y = 9/2 + 3/2
y = 12/2
y = 6
so ur missing value is 6...a (or y) = 6
In exponential form: 10^2=3(x+5)
If we were to solve, x=85/3
Nitrogen Radius = 5.8 x 10⁻¹¹ m
Beryllium Radius = 1.12 x 10⁻¹⁰ m
Let's find the quotient of N/Be :
(5.8x10⁻¹¹)/(1.12x10⁻¹⁰). But 10⁻¹¹/10⁻¹⁰ = 10⁽⁻¹¹⁺¹⁰⁾ = 10⁻¹ = 1/10 = 0.1
→ (5.8/1.12).(0.1) = 0.58/1.12 = 0.518.
Conclusion: the radius of Be is almost double than the radius of N
C, always go with supervisors
