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Leokris [45]
3 years ago
7

Pre-calc: Write a degree 3 polynomial with zeros 2, 4, -3

Mathematics
1 answer:
leva [86]3 years ago
5 0

Answer:

x³-3x²-10x+24

Step-by-step explanation:

Ha, you're in luck; I just learned this last week

Zeros: 2, 4, -3

(x-2)(x-4)(x+3) (I will be multiplying the zeros 2 and 4 first)  ——Distributive Property

(x²-4x-2x+8)(x+3) ––Combine like terms

(x²-6x+8)(x+3) ––Distibutive Property

x³+3x²-6x²-18x+8x+24 ––Combine like terms

x³-3x²-10x+24 ––Final answer, to the third degree

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1x -8 &lt; 2x + 1<br> What is the largest integer value that makes this inequality true
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Answer:

The largest integer value that makes the inequality true is 9.

General Formulas and Concepts:
<u>Algebra I</u>

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

1x - 8 < 2x + 1

<u>Step 2: Solve for </u><u><em>x</em></u>

  1. Simplify:                                                                                                            x - 8 < 2x + 1
  2. [Subtraction Property of Equality] Subtract <em>x</em> on both sides:                        -8 < x + 1
  3. [Subtraction Property of Equality] Subtract 1 on both sides:                        -8 < x
  4. Rewrite:                                                                                                           x > -8

∴ we see that any number <em>x greater than -8</em> would work as a solution to the inequality. That would mean the next largest integer, 9, would be our answer.

---

Topic: Algebra I

7 0
2 years ago
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