Nitrogen Radius = 5.8 x 10⁻¹¹ m
Beryllium Radius = 1.12 x 10⁻¹⁰ m
Let's find the quotient of N/Be :
(5.8x10⁻¹¹)/(1.12x10⁻¹⁰). But 10⁻¹¹/10⁻¹⁰ = 10⁽⁻¹¹⁺¹⁰⁾ = 10⁻¹ = 1/10 = 0.1
→ (5.8/1.12).(0.1) = 0.58/1.12 = 0.518.
Conclusion: the radius of Be is almost double than the radius of N
Answer:
I think the answer is 200cm^2
Step-by-step explanation:
since the square is divided into eight equal parts
and one shaded part is =25cm^2
multiply the area of the shaded part by the number of equal parts
= 25cm^2 ×8
= 200cm^2
Answer:
Step-by-step explanation:
<u>Volume of the pyramid:</u>
<u>Volume of the prism:</u>
<u>Since all dimensions remain as is, the volume of the prism is:</u>
- lwh / (lwh/3) = 3 times greater
Answer:
23
Step-by-step explanation:
3.47 = 3 sig. figs.
6.7 = 2 sig. figs.
Since these two numbers are being multiplied, you would round to the smallest number of sig. figs. of the two. In this case, it would be 2 significant figures.
3.47 * 6.7 = 23.249 (dont forget to round to 2 sig. figs. ) --> 23
