Need help presenting this solution on and number line and in interval notation. (I’m absolutely clueless haha)

Mathematics

1 answer:

beks73 [17]2 years ago

8 0

Since the number is a fraction make a number line using fractions. The inequality sign includes being equal to, so add a solid dot on -5/2 and since x is less than that, draw an arrow pointing to the left.

See attached drawing.

For interval notation since x can be any number less than or equal to -5/2 it would be written as (-∞, -5/2]

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Charlie has $3.15 in his bank which contains only nickels and dimes. There are 9 more nickels than dimes. Find the number he has

Brrunno [24]

Charlie has $3.15 in his bank which contains only nickels and dimes. There are 9 more nickels than dimes. Then Number of dimes =18

and Number of nickels =27

<h3>What is basic algebra ?</h3>

Mathematical expressions can be used to depict situations or issues, and algebra is the field of mathematics that does this. For a mathematical expression to have meaning, it needs to include variables like x, y, and z as well as mathematical operations like addition, subtraction, multiplication, and division. Algebra is used in every area of mathematics, including coordinate geometry, calculus, and trigonometry. A straightforward algebraic expression is 2x + 4 = 8.

Given that : Charlie has $3.15 in his bank which contains only nickels and dimes. There are 9 more nickels than dimes

Let d be the number of dimes

d + 9 = Number of nickels

A dime = 0.1

nickle is = 0.05

0.1d + 0.05d + 0.45 = 3.15

0.15d = 2.7

d = 18

Number of dimes =18

Number of nickels = 18 + 9

=27

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1 year ago

The following observations 40, 42, 45, x-1, x +1, 51, 54, 62 are arranged in

Harlamova29_29 [7]

Step-by-step explanation:

Here n = 8 (even number)

$\therefore \: \frac{n}{2} = \frac{8}{2} = 4 \\ \\\&\:\: \frac{n}{2} + 1 = 4 + 1 = 5 \\ \\ hence \: \\ median = \frac{ {4}^{th} term + {5}^{th} term}{2} \\ \\ \therefore \: 49 = \frac{x - 1 + x + 1}{2} \\ \\ \therefore \: 49 = \frac{2x}{2} \\ \\ \therefore \: 49 = x \\ \\ \huge \purple { \boxed{\therefore \: x = 49}}$