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fenix001 [56]
3 years ago
5

188 ASU students, faculty and staff were randomly surveyed and asked if they have an ASU parking decal, ride their bike to campu

s, or ride the Light Rail. Here are the results:  77 said they have an ASU parking decal  75 said they ride their bike to campus  91 said they ride the Light Rail  12 people have an ASU parking decal, ride their bike, and ride the Light Rail  18 people have an ASU parking decal and ride the Light Rail  39 people ride their bike to campus and ride the Light Rail  20 people have a parking decal and ride their bike to campus a. Draw an accurate Venn diagram to represent this situation. b. How many respondents ride the Light Rail and ride their bike to campus? c. How many respondents only have an ASU parking decal? d. How many respondents ride the Light Rail or has an ASU decal? e. Shade the area on your Venn diagram that represents people who have a parking decal or who ride their bike to campus but who do not ride the Light Rail.

Mathematics
1 answer:
bulgar [2K]3 years ago
8 0
Part A.
The venn diagram is attached. In the venn diagram, circle A represent the number of responds that have an ASU parking deal. Circle B represent the number of respondents that ride their bike to campus and circle C represent the number of respondents that that ride the Light Rail.

Part B.
From the venn diagram, the number of respondents that ride the Light Rail and ride their bike to campus is given by 39 – 12 = 27

Part C.
From the venn diagram, the number of respondents that only have an ASU parking decal is given by <span>77 – 12 – 8 – 6 = 51

Part D.
The number of respondents that ride the Light Rail or have an ASU decal is given by the sum of the number of respondents that ride the Light Rail only and those that have an ASU parking decal and those that have both ASU parking decal and ride their bike to school.
This is given by 51 + 8 + 28 = 87.

Part E.
The venn diagram showing the area </span><span>that represents people who have a parking decal or who ride their bike to campus but who do not ride the Light Rail</span> sgaded is attached.

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6 x +38 (+112) = 180 degree as angles on a straight line add up to 180   6 x +38 (+112) = 180    6 x +140 = 180  6 x + 140- 140 = 180-140      6 x  = 40   x = 40/6  x = 6.66666667    x = 6 2/3  <u> </u><u>Proof  (6( 6 2/3)) + 38 + 112 = 180</u>     = (40+38)+112 = 180 = 78 +112 = 180   Proves the supplementary angle is 78 degree.

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