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3 years ago

Solve x2 + 8x + 22 = 0 by completing the square.

Mathematics

1 answer:

Liula [17]3 years ago

6 0

Answer:

Step-by-step explanation:

the solution of a squared equation is

x = (-b ± sqrt(b² - 4ac)) / (2a)

in our case

a = 1

b = 8

c = 22

x = (-8 ± sqrt(64 - 88))/2 = (-8 ± sqrt(-24))/2 =

= (-8 ± sqrt(4×-6))/2 = (-8 ± 2×sqrt(-6))/2 =

= -4 ± sqrt(-6) = -4 ± i×sqrt(6)

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Write as a unit rate: 36 gallons to 9 minutes *

Nataly_w [17]

Answer

36/9= 4

Step-by-step explanation:

This is a fraction equal to

36 gallons ÷ 9 minutes

We want a unit rate where

1 is in the denominator,

so we divide top and bottom by 9

36 gallons ÷ 9

9 minutes ÷ 9

4 gallons

1 minute

4 gallons

minute

= 4 gallons per minute

7 0

3 years ago

Write the eqauation of a line that has the slope pf 6 passes through (-3,5)

Darina [25.2K]

Y = mx + b
slope(m) = 6
(-3,5)...x = -3 and y = 5
now we sub and find b, the y int
5 = 6(-3) + b
5 = -18 + b
5 + 18 = b
23 = b

so ur equation is : y = 6x + 23

6 0

3 years ago

Find the area of each circle round to the nearest tenth use 20 yard

stiv31 [10]

Answer:

Step-by-step explanation:

3 0

3 years ago

1 meter lightining cable weight 85 grams empty spool weight is 260 gram he have total weight 1540gram what is the answer

mrs_skeptik [129]

According to the information given in the exercise:

• 1 meter of lightning cable weight 85 grams.

• An empty spool weighs 260 grams.

• Ted weighs the partly used spool shown in the picture and its total weight is 1540 grams.

Then, knowing this, let be "x" the number of meters of cable left on the spool.

You can set up the following using the information given in the exercise:

$Total\text{ }weight=Empty\text{ }spool+85(Meters\text{ }of\text{ }cable)$

Knowing that:

$\begin{gathered} Total\text{ }weight=1540 \\ Empty\text{ }spool=260 \end{gathered}$

You can set up that:

$1540=260+85x$

Therefore, solving for "x", you get:

$\begin{gathered} 1540-260=85x \\ \\ \frac{1540-260}{85}=x \end{gathered}$ $x\approx15.059$

Hence, you can conclude that the answer is: Second option.

5 0

1 year ago

What binomial do you have to add to the polynomial:

marshall27 [118]

Answer:

a) $-2x^2+5xy$

b) $-3y^2+5xy$

Step-by-step explanation:

Given polynomial : $2x^2+3y^2-5xy+1$

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable x is:

$-2x^2+5xy$

$(2x^2+3y^2-5xy+1)+(-2x^2+5xy)$

$=2x^2+3y^2-5xy+1-2x^2+5xy$

$=2x^2-2x^2+3y^2-5xy+5xy+1$

$=3y^2+1$

Given polynomial : $2x^2+3y^2-5xy+1$

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable y is:

$-3y^2+5xy$

$(2x^2+3y^2-5xy+1)+(-3y^2+5xy)$

$=2x^2+3y^2-5xy+1-3y^2+5xy$

$=2x^2+3y^2-3y^2-5xy+5xy+1$

$=2x^2+1$

7 0

2 years ago