All categories

3 years ago

Solve x2 + 8x + 22 = 0 by completing the square.

Mathematics

1 answer:

Liula [17]3 years ago

6 0

Answer:

Step-by-step explanation:

the solution of a squared equation is

x = (-b ± sqrt(b² - 4ac)) / (2a)

in our case

a = 1

b = 8

c = 22

x = (-8 ± sqrt(64 - 88))/2 = (-8 ± sqrt(-24))/2 =

= (-8 ± sqrt(4×-6))/2 = (-8 ± 2×sqrt(-6))/2 =

= -4 ± sqrt(-6) = -4 ± i×sqrt(6)

You might be interested in

At a publishing company 60% of the editors are female.

Anna35 [415]

0.3 percent because 50% of 60% is 0.3%

8 0

3 years ago

A. a 10 8 6 14 2 -10-8-6 -4 6 810 4 6 18 10 Is this a function? Yes No How do you know?

alina1380 [7]

Its a function if there are different numbers as each x value but if there are multiple of the same number in the x value it isn't a function

5 0

3 years ago

In a particular sequence, each term is 3 times the last. The sequence begins with 2,6,18. Write the next four terms of the seque

laiz [17]

Answer:

54, 162, 486, 1458

Step-by-step explanation:

To obtain the next term in the sequence multiply the previous term by 3

18 × 3 = 54

54 × 3 = 162

162 × 3 = 486

486 × 3 = 1458

3 0

3 years ago

EEEEEEEEEEEEEEEE!!!✨

marishachu [46]

Answer:

it should be <...........

5 0

3 years ago

Read 2 more answers

2x+7y=-6 4x-y=18\ show step by step how it is solved

abruzzese [7]

Answer: (60/13, 6/13)

Concept:

There are three general ways to solve systems of equations:

Elimination
Substitution
Graphing

Here, we are going to use elimination since all the variables are in the corresponding position.

Solve:

Given

$\left \{ {{2x+7y=-6} \atop {4x - y=18}} \right.$

Multiply the first equation in order to eliminate [x]

$\left \{ {{4x + 14y = -12} \atop {4x - y = 18}} \right.$

Subtract the second equation from the first equation to eliminate [x]

$14y-y=-12+18$

$13y=6$

Divide 13 on both sides

$13y/13=6/13$

$\boxed{y=\frac{6}{13} }$

Substitute [y] value in order to get [x] value

4x - y = 18

4x - 6/13 = 18

4x = 18 + 6/13

4x = 240/13

$\boxed{x=\frac{60}{13} }$

Hope this helps!! :)

Please let me know if you have any questions

4 0

3 years ago