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Luda [366]
2 years ago
12

36 for 4 baseball hats ;56 for 7 baseball hats are they equivalent

Mathematics
2 answers:
meriva2 years ago
8 0
I believe that they are
Akimi4 [234]2 years ago
6 0
No, they're not equivalent....... i suggest a calculator for this kind of math, just divide the first number by the last and compare them, like this 36/4=9, 56/7=8

the first one is $9 per hat, and the second one is $8 per hat
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Answer and Explanation:

The probability of flipping a coin to get heads is 1/2 or 50%. If you multiply this, by how many times you flip it, or 1/2 * 1/2 * 1/2, then you get 1/8 or 12.5% chance that she will get heads 3 times in a row

4 0
3 years ago
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Answer:

Not independent

Step-by-step explanation:

For two events to be independent, they must not effect each other. For two independent events, changes in one of the event do not cause any change on the other event.

To explain it in terms of probability, let's first define and calculate the probabilities:

P(F) : Probability of facing felony

P(C) : Probability of going to college

P(F ∩ C) : Probability of facing felony and going to college

P(F° ∩ C): Probability of not facing a felony and going to college

Assume we have 100 students:

Faced felony = 0.3 * 100 = 30

Faced felony and go college = 30 * 0.4 = 12

Not faced felony = 0.7 * 100 = 70

Not faced felony and go college = 0.6 * 70 = 42

Total of going to college = 12 + 42 = 54

So P(C) = 54 / 100 = 0.54

If P(F)*P(C) = P(F ∩ C), then these two events are independent. If not, they are not independent.

Let's calculate the probabilities:

As given in the question, 30% of students face felony so P(F) = 0.3

P(C) = P(C ∩ F) + P(C ∩ F°) = 0.12 + 0.42 = 0.54

P(F) = 0.3

P(F ∩ C) = 0.12

P(F)*P(C) = 0.3 * 0.54 = 0.162 which ic not equal to P(F ∩ C). Therefore, these events are not independent.

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