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Alina [70]
3 years ago
13

Entd OOOO OC Clear a -8 6 4 222 Y intercept

Mathematics
1 answer:
Nata [24]3 years ago
3 0

Answer:

idk

Step-by-step explanation:

I feel bad but I dont know

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Consider the function f(x)= (x+4)(x-2) what is the equation of the axis of symmetry
almond37 [142]

if we zero out f(x), namely make y = 0, we can get the roots or x-intercepts for this quadratic equation

\bf 0 = (x+4)(x-2)\implies \begin{cases} 0=x+4\implies &-4=x\\ 0=x-2\implies &2=x \end{cases}

now, the equation is in x-terms, meaning is a vertically opening parabola, so the axis of symmetry will be x = something, a vertical line.

well, we have two x-intercepts, one at -4 and another at 2, and the vertex is right half-way between those guys

-4------------(-1)------------2

so the vertex is at x=-1, namely the axis of symmetry is x = -1.

8 0
3 years ago
The function of (x) varies directly with x^2, and f(x)=96 when x=4 what is the value of f(2)
makkiz [27]
\bf \qquad \qquad \textit{direct proportional variation}
\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------

\bf \textit{f(x) varies directly with }x^2\qquad f(x)=kx^2
\\\\\\
\textit{we also know that }
\begin{cases}
f(x)=96\\
x=4
\end{cases}\implies 96=k(4)^2\implies 96=16k
\\\\\\
\cfrac{96}{16}=k\implies 6=k\qquad therefore\qquad \boxed{f(x)=6x^2}
\\\\\\
\textit{now, when }\stackrel{f(2)}{x=2}\textit{ what is \underline{f(x)}?}\qquad f(2)=6(2)^2
3 0
3 years ago
For the graph shown, select the statement that best represents the given system of equations. Number graph ranging from negative
Bumek [7]
This system of equations is consistent and independent, because there is only one solution. the answer is C
7 0
3 years ago
Read 2 more answers
Which of the following statements does not describe the structure of an atom?
blagie [28]

Answer:

B) Inside the nucleus of an atom are protons and electrons.

Explanation:

Inside the nucleus of an atom are protons and neutrons. Electrons orbit (kind of?) away from the nucleus.

8 0
2 years ago
What are the coordinates of the point on the directed line segment from (-6, -3) to
melamori03 [73]

Given:

A point divides a directed line segment from (-6, -3) to (5,8) into a ratio of 6 to 5.

To find:

The coordinates of that point.

Solution:

Section formula: If point divides a line segment in m:n, then the coordinates of that point are

Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

A point divides a directed line segment from (-6, -3) to (5,8) into a ratio of 6 to 5. Using section formula, we get

Point=\left(\dfrac{6(5)+5(-6)}{6+5},\dfrac{6(8)+5(-3)}{6+5}\right)

Point=\left(\dfrac{30-30}{11},\dfrac{48-15}{11}\right)

Point=\left(\dfrac{0}{11},\dfrac{33}{11}\right)

Point=\left(0,3\right)

Therefore, the coordinates of the required point are (0,3).

3 0
3 years ago
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