She should move it one place to the left because there is one zero in ten so however many zeros there are in the multiple of 10 that's how many times you move it. Then, you move it left to divide and right to multiply. Hope I helped!
Answer:
Step-by-step explanation:
I always like to use the mean if I can. In this data set, it's probably not a very good idea. Too much weight is given to that 7.2 and the two 3.2s.
I would choose the median, because the mode is the same answer and that's a good enough reason for choosing anything. 2 out 3 isn't bad as they say in Baseball.
Answer:
280000lb
Step-by-step explanation:
In this question, we shall be calculating the amount of carbon iv oxide prevented from entering the atmosphere.
Generally we know that 1kwh produces 1.37 lbs of Carbon iv oxide in the atmosphere
Now, using a 100 watt light bulb daily for 8 hours, for a year, the amount of Carbon iv oxide produced will be;
100 * 1.37 * 8 * 365 = 40040 lb
Using a 30 watt CFL for 8hrs/ day for a year, we have;
30 * 1.37 * 8 * 365 = 120012 lb
Now calculating the amount of CO2 prevented, we have 40040 - 120012 = 280028 lb = 280000 after rounding up
The best answer is 1.435 ·103 because while they both are really small for a rail road track that one is bigger. the final answer for that is 147.805mm.
