Which of the following is the sum of the slopes of the line 3x+y=1 and a line perpendicular to this line? A 0 B 13 C −83 D −6
1 answer:
Answer:
-8/3
Step-by-step explanation:
First find the slope of the line
3x+y = 1
Solve for y
y = -3x+1
This is in slope intercept form
y = mx+b where m is the slope
The slope is -3
The slopes of perpendicular lines multiply to -1
m* -3 = -1
m = 1/3
The line perpendicular has a slope of 1 / (3) = 1/3
The sum is -3 + 1/3
-9/2 + 1/3 = -8/3
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