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4 years ago

Which of the following is the sum of the slopes of the line 3x+y=1 and a line perpendicular to this line? A 0 B 13 C −83 D −6

Mathematics

1 answer:

laiz [17]4 years ago

3 0

Answer:

-8/3

Step-by-step explanation:

First find the slope of the line

3x+y = 1

Solve for y

y = -3x+1

This is in slope intercept form

y = mx+b where m is the slope

The slope is -3

The slopes of perpendicular lines multiply to -1

m* -3 = -1

m = 1/3

The line perpendicular has a slope of 1 / (3) = 1/3

The sum is -3 + 1/3

-9/2 + 1/3 = -8/3

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The product of 3 consecutive even integers is equal to the cube of the first plus the square of the second plus twice the square

algol [13]

Answer:

6, 8 and 10 and -2, 0, 2

There are two roots x = -2 and 6,

but the since I don't believe 0 is an even number the answer is 6, 8 and 10

I was incorrect according to G0ggle zero is an even number so another answer is -2, 0, 2

Step-by-step explanation:

read the question and convert the English to mathematics

x, y and z even consecutive number

y = x+2

z = y+2 = x+4

and

xyz = x³ + y² + 2z² substitiute x terms in for y and z

x(x+2)(x+4) = x³ + (x+2)² + 2(x+4)² solve for x by graphing on DEMOS

x = -2, 6 solved algebraically below

x = -2 y=0 z=2

x = 6 y=8 z=10

Checked both answers

xyz = x³ + y² + 2z²

-2(0)2 = -8 + 0 + 8 when x = -2

0 = 0

and

6(8)(10) = 6³ + 8² +2(10)² when x = 6

480 = 216+64+200

= 480

x(x+2)(x+4) = x³ + (x+2)² + 2(x+4)² solved algebraically

(x²+2x)(x+4) = x³ + x² +4x +4 + 2x² + 16x + 32

x³ + 6x² + 8x = x³ + x² +4x +4 + 2x² + 16x + 32

x³ + 6x² + 8x = x³ + 3x² + 20x + 36

3x² - 12x - 36 = 0 factor out the 3

3[x² - 4x - 12] = 0

3(x+2)(x-6) = 0 x = -2 and -12

6 0

3 years ago

5. Algebra Write an expression you can

AveGali [126]

Answer:

y=x^3

Step-by-step explanation:

I don't know y sha

6 0

3 years ago

Define table represents a group frequency discretion of the number of hours spent on the computer per week for 49 student. What

Scilla [17]

Observe the given data distribution table carefully.

The 5th class interval is given as,

$14.0-17.4$

The upper limit (UL) and lower limit (LL) of this interval are,

$\begin{gathered} UL=17.4 \\ LL=14.0 \end{gathered}$

Thus, the upper-class limit of this 5th class is 17.4.

6 0

1 year ago

During a test period, an experimental group of 10 vehicles using an 85 percent ethanol-gasoline mixture showed mean CO2 emission

Zinaida [17]

Answer:

-1.683

Step-by-step explanation:

Given :

Group 1 :

x1 = 667 ; n1 = 10 ; s1 = 20

Group 2 :

x2 = 679 ; n2 = 14 ; s2 = 15

The test statistic assuming equal variance :

x1 - x2 / √[Sp² * (1/n1 + 1/n2)]

sp² = [(n1 - 1)*s1² + (n2 - 1)*s2²] ÷ (n1 + n2 - 2)

Sp² = [(10 - 1)*20² + (14 - 1)*15²] = 296.59

Test statistic =

(667 - 679)/ √[296.59 * (1/10 + 1/14)]

-12 / 7.1304978

Test statistic = - 1.682

8 0

3 years ago

Find the slope of the line that contains the following points. R(-3, 5), S(3, -2) 7/6 7/6 undefined

Musya8 [376]

Answer:

-\frac{7}{6}

Step-by-step explanation:

We can use the slope formula for the segment that joins any two points $(x_1, y_1)$ and $(x_2, y_2)$ :

$slope=\frac{y_2-y_1}{x_2-x_1}$

which in our case gives:

$slope=\frac{y_2-y_1}{x_2-x_1} = \frac{-2-5}{3-(-3)}=\frac{-7}{6} =-\frac{7}{6}$

5 0

3 years ago