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Monica [59]
3 years ago
11

Which of the following is the sum of the slopes of the line 3x+y=1 and a line perpendicular to this line? A 0 B 13 C −83 D −6

Mathematics
1 answer:
laiz [17]3 years ago
3 0

Answer:

-8/3

Step-by-step explanation:

First find the slope of the line

3x+y = 1

Solve for y

y = -3x+1

This is in slope intercept form

y = mx+b where m is the slope

The slope is -3

The slopes of perpendicular lines multiply to -1

m* -3 = -1

m = 1/3

The line perpendicular has a slope of 1 / (3) = 1/3

The sum is -3 + 1/3

-9/2 + 1/3 = -8/3

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Answer:

y = 4x - 1

Step-by-step explanation:

Equation y = 4x - 1 matches the function described in the table.

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Answer:

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3 years ago
-2x - 6y = -24<br> X-8y = -10
Debora [2.8K]

Answer:

x = -26 and y = -2

I hope this is the answer you are looking for

Step-by-step explanation:

x-8y = -10 => add 8y to both sides

+8y = +8y

x = -10+8y

-2(-10+8y) -6y = -24 => intersect what you got into the first equation

20-16y-6y = -24 => Distribute the -2

20-22y     = -24 => subtract 20 in both sides

-20           = -20

-22y = -44 => divided by -22 in both sides

/-22 = /-22

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x+16 = -10 => multiply -8*-2

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3 years ago
What are the solutions to the quadratic equation x^2-16=0
Paha777 [63]

Answer:

x = ±4

Step-by-step explanation:

Hi there!

x^2-16=0

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x^2=16

Take the square root of both sides

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I hope this helps!

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2 years ago
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