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Afina-wow [57]
3 years ago
12

Let x = 4. What is the value of y in the equation y = 15 + 11 + x?

Mathematics
1 answer:
marishachu [46]3 years ago
5 0
Okay so you have to add up 15 and 11 and 4 so your answer is y=30


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Complete the table for the given rule. Rule: y=x-3y=x−3y, equals, x, minus, 3 xxx y 777 111 77
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Rule: y = x-3

Answer:

The table given

x, y

7,3

3,1

3,7

 

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Line segment AB has endpoints at A (-4,4) and (8,8). Find and plot its image after a dilation with a center at the origin and a
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Step-by-step explanation:

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3 years ago
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
ale4655 [162]

Answer:

6.26-2.01\frac{2.47}{\sqrt{50}}=5.56    

6.26+2.01\frac{2.47}{\sqrt{50}}=6.96    

So on this case the 95% confidence interval would be given by (5.56;6.96)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=6.26

The sample deviation calculated s=2.47

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=50-1=49

Assuming a Confidence of 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that t_{\alpha/2}=2.01

Now we have everything in order to replace into formula (1):

6.26-2.01\frac{2.47}{\sqrt{50}}=5.56    

6.26+2.01\frac{2.47}{\sqrt{50}}=6.96    

So on this case the 95% confidence interval would be given by (5.56;6.96)    

6 0
3 years ago
3 8<br> - ÷ - what is that<br> 4 9
Komok [63]
The answer would be:

Fraction: 27/32

Decimal: 0.84375
7 0
3 years ago
19.5 is 0.75% of what?
bulgar [2K]
The answer is 0.75%*19.5=(0.75÷100)*19.5=(0.75*19.5)÷100=14.625÷100=0.146225. 0.14;
7 0
3 years ago
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