Answer:
C. 8
Step-by-step explanation:
![\because \: {s}^{3} = 64 \\ s = \sqrt[3]{64} \\ s = 4 \\ side \: of \: cube = 4 \: units \\ when \: side \: is \: halved \\ new \: side \: length = \frac{4}{2} = 2 \\ \: new \: volume = {2}^{3} = 8 \: cubic \: units](https://tex.z-dn.net/?f=%20%5Cbecause%20%5C%3A%20%20%7Bs%7D%5E%7B3%7D%20%20%3D%2064%20%5C%5C%20s%20%3D%20%20%5Csqrt%5B3%5D%7B64%7D%20%20%5C%5C%20s%20%3D%204%20%5C%5C%20side%20%5C%3A%20of%20%5C%3A%20cube%20%3D%204%20%5C%3A%20units%20%5C%5C%20when%20%5C%3A%20side%20%5C%3A%20is%20%5C%3A%20halved%20%5C%5C%20new%20%5C%3A%20side%20%5C%3A%20length%20%3D%20%20%5Cfrac%7B4%7D%7B2%7D%20%20%3D%202%20%5C%5C%20%20%5C%3A%20new%20%5C%3A%20volume%20%3D%20%20%7B2%7D%5E%7B3%7D%20%20%3D%208%20%5C%3A%20cubic%20%5C%3A%20units)
All real numbers except -4 and 9.
The domain of an expression is the range of all values for which the expression is defined. Looking at the expression, it will legal everywhere except when a^2 - 5a - 36 is equal to 0. Since that's a quadratic equation, we can use the quadratic formula to find where its value is 0, giving -4 and 9.
Therefore the domain of the expression is, All real numbers except -4 and 9.
Well
You take the thing
You make sure a very good amount of light is pointing at the microscope
And then you turn the zoom-in or zoom-out
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